如何在SQL中获取上一个和最新日期及其详细信息

Question

我有一个包含以下数据的表:

create table tempdata(account varchar2(20)not null,bookid number(10),seqno number(20) not null,book_date date, book1 number(10),
book2 number(10),book3 number(10))

insert into tempdata values('123',101,09,add_months((sysdate),-1),100,120,130);

insert into tempdata values('123',101,10,sysdate),70,60,100)

select * from tempdata;

ACCOUNT BOOKID  SEQNO   BOOK_DATE               BOOK1   BOOK2   BOOK3

123      101     9      9/22/2015 10:05:28 AM   100      120    130

123      101     10     10/22/2015 10:01:42 AM  70       60     100

我需要输出类似下面的内容,以便创建另一个临时表,其中包含最新的书籍详细信息,包括上一个日期和最新日期:

ACCOUNT BOOKID  SEQNO     Previous_DATE          Latest_date           BOOK1    BOOK2   BOOK3

123      101     10    9/22/2015 10:05:28 AM  10/22/2015 10:01:42 AM          70     60      100

Answer 1

在这里，我假设您需要唯一account和bookid组合的数据。

SELECT T1.ACCOUNT, T1.BOOKID, T1.SEQNO,T1.PREVIOUS_DATE, 
T1.BOOK_DATE AS  LATEST_DATE , T1.BOOK1, T1.BOOK2, T1.BOOK3 
FROM (
    SELECT T.* ,ROW_NUMBER() OVER (PARTITION BY ACCOUNT,bookid ORDER BY BOOK_DATE desc) as rno, 
    LAG(TO_CHAR(BOOK_DATE), 1, 0) OVER (ORDER BY BOOK_DATE) AS PREVIOUS_DATE 
    FROM TEMPDATA T) T1
WHERE T1.RNO =1