Python - 可以在不明确使用名称的情况下调用自身吗？

Question

或者更广泛的问题:如何在python中创建递归函数,并且在更改其名称时,只需要在声明中进行更改？

Answer 1

我找到了一个简单有效的解决方案。

from functools import wraps

def recfun(f):
    @wraps(f)
    def _f(*a, **kwa): return f(_f, *a, **kwa)
    return _f

@recfun
# it's a decorator, so a separate class+method don't need to be defined
# for each function and the class does not need to be instantiated,
# as with Alex Hall's answer
def fact(self, n):
    if n > 0:
        return n * self(n-1)  # doesn't need to be self(self, n-1),
                              # as with lkraider's answer
    else:
        return 1

print(fact(10))  # works, as opposed to dursk's answer