我是PHP和PDO的新手,我正在尝试创建一个简单的登录系统.现在,我正在尝试从我的表中获取id和密码,以与用户输入的密码进行比较(我使用单向加密方式加盐).所以,现在问题是,当我这样做时$password = $stmt->fetchColumn(1),我的登录系统工作.现在,当我尝试以前id做的$id = $stmt->fetchColumn(0)时候$password,我不能再登录了,我得到了"错误的用户名/密码"错误.
现在我很确定我做错了fetchColumn但我无法理解.
这是一个有效的代码片段:
$con = new PDO( DB_DSN, DB_USERNAME, DB_PASSWORD );
//set how pdo will handle errors
$con->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
//this would be our query.
$sql = "SELECT id, password FROM user_admin WHERE email = :email";
//prepare the statements
$stmt = $con->prepare( $sql );
//give value to named parameter :email
$stmt->bindValue( "email", $this->email, PDO::PARAM_STR );
$stmt->execute();
$password = $stmt->fetchColumn(1);
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现在以下不起作用.请注意,当我添加$id:
$con = new PDO( DB_DSN, DB_USERNAME, DB_PASSWORD );
//set how pdo will handle errors
$con->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
//this would be our query.
$sql = "SELECT id, password FROM user_admin WHERE email = :email";
//prepare the statements
$stmt = $con->prepare( $sql );
//give value to named parameter :email
$stmt->bindValue( "email", $this->email, PDO::PARAM_STR );
$stmt->execute();
$id = $stmt->fetchColumn(0); //That's the problem
$password = $stmt->fetchColumn(1);
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任何帮助是极大的赞赏.
从文档:
PDOStatement :: fetchColumn - 从结果集的下一行返回单个列
每次调用fetchColumn它都会前进到结果集的下一行.
尝试使用PDOStatement::fetch替代方法将整个行作为数组获取,然后从那里访问值.
$stmt->execute();
$row = $stmt->fetch();
$id = $row[0];
$password = $row[1];
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