Bor*_*lik 0 string perl scalar numbers
请考虑以下代码及其输出:
#!/usr/bin/perl -w
use strict;
use Data::Dumper;
my $HOURS_PER_DAY = 24.0 * 1.0;
my $BSA = 1.7 * 1.0;
my $MCG_PER_MG = 1000.0 * 1.0;
my $HOURS_DURATION = 20.0 * $HOURS_PER_DAY;
my $dummy = $HOURS_PER_DAY * $BSA * $MCG_PER_MG * $HOURS_DURATION;
print Dumper($HOURS_PER_DAY);
print Dumper( $BSA);
print Dumper( $MCG_PER_MG);
print Dumper( $HOURS_DURATION );
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$VAR1 = 24;
$VAR1 = '1.7';
$VAR1 = 1000;
$VAR1 = 480;
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如您所见,第二个变量被视为字符串,而第一个和第四个变量被视为数字.任何人都知道底层逻辑是什么?
编辑添加的算术计算并不能完全解决问题(参见$ BSA变量).
$ perl -v
This is perl, v5.10.0 built for cygwin-thread-multi-64int
(with 6 registered patches, see perl -V for more detail)
Copyright 1987-2007, Larry Wall
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Data :: Dumper的工作是序列化数据,你不能很好地了解perl在内部使用基于其输出的数据.该杰韦利::皮克模块可以转储保存在变量的基本标志和值.Devel :: Peek POD解释了旗帜的重要性.
#!/usr/bin/perl
use warnings;
use strict;
use Devel::Peek;
my $HOURS_PER_DAY = 24.0 * 1.0;
my $BSA = 1.7 * 1.0;
my $MCG_PER_MG = 1000.0 * 1.0;
my $HOURS_DURATION = 20.0 * $HOURS_PER_DAY;
my $dummy = $HOURS_PER_DAY * $BSA * $MCG_PER_MG * $HOURS_DURATION;
Dump($HOURS_PER_DAY);
Dump($BSA);
Dump($MCG_PER_MG);
Dump($HOURS_DURATION);
__END__
SV = PVNV(0xd71ff0) at 0xd87f90
REFCNT = 1
FLAGS = (PADBUSY,PADMY,IOK,NOK,pIOK,pNOK)
IV = 24
NV = 24
PV = 0
SV = PVNV(0xd71fc8) at 0xd87f60
REFCNT = 1
FLAGS = (PADBUSY,PADMY,NOK,pIOK,pNOK)
IV = 1
NV = 1.7
PV = 0
SV = PVNV(0xd72040) at 0xd87f40
REFCNT = 1
FLAGS = (PADBUSY,PADMY,IOK,NOK,pIOK,pNOK)
IV = 1000
NV = 1000
PV = 0
SV = IV(0xd8b408) at 0xd87f30
REFCNT = 1
FLAGS = (PADBUSY,PADMY,IOK,pIOK)
IV = 480
# compare the above output to output without the assignment to $dummy:
SV = IV(0x7b0eb8) at 0x7adf90
REFCNT = 1
FLAGS = (PADBUSY,PADMY,IOK,pIOK)
IV = 24
SV = NV(0x7c7c90) at 0x7adf60
REFCNT = 1
FLAGS = (PADBUSY,PADMY,NOK,pNOK)
NV = 1.7
SV = IV(0x7b13d8) at 0x7adf40
REFCNT = 1
FLAGS = (PADBUSY,PADMY,IOK,pIOK)
IV = 1000
SV = IV(0x7b1408) at 0x7adf30
REFCNT = 1
FLAGS = (PADBUSY,PADMY,IOK,pIOK)
IV = 480
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Perl将变量视为字符串或数字的整个概念存在缺陷.当你需要时,Perl会以正确的方式处理你的变量,例如,算术运算符总是将它们的参数视为数字(假设你没有滥用运算符重载或其他类似的变量).
你不应该担心这个:Perl知道它在做什么.
Data :: Dumper在变量的字符串表示上使用简单模式来确定它是否是数字.从源代码:
...
elsif ($val =~ /^(?:0|-?[1-9]\d{0,8})\z/) { # safe decimal number
$out .= $val;
}
else { # string
...
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这与具有小数点的数字不匹配,这解释了您观察到的行为.
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