将Cookie设置为在一天后过期

Question

我使用了我从git获得的代码.它基本上设置为设置一个cookie,以便在第一次访问该站点时显示弹出窗口.但是,我希望它只能设置24小时.因此,如果某人在一两天内回到该网站,它将再次显示.

(function ($) {

    'use strict';

    $.fn.firstVisitPopup = function (settings) {

        var $body = $('body');
        var $dialog = $(this);
        var $blackout;
        var setCookie = function (name, value) {
            var date = new Date(),
                expires = 'expires=';
            date.setTime(date.getTime() + 31536000000);
            expires += date.toGMTString();
            document.cookie = name + '=' + value + '; ' + expires + '; path=/';
        }
        var getCookie = function (name) {
            var allCookies = document.cookie.split(';'),
                cookieCounter = 0,
                currentCookie = '';
            for (cookieCounter = 0; cookieCounter < allCookies.length; cookieCounter++) {
                currentCookie = allCookies[cookieCounter];
                while (currentCookie.charAt(0) === ' ') {
                    currentCookie = currentCookie.substring(1, currentCookie.length);
                }
                if (currentCookie.indexOf(name + '=') === 0) {
                    return currentCookie.substring(name.length + 1, currentCookie.length);
                }
            }
            return false;
        }
        var showMessage = function () {
            $blackout.show();
            $dialog.show();
        }
        var hideMessage = function () {
            $blackout.hide();
            $dialog.hide();
            setCookie('fvpp' + settings.cookieName, 'true');
        }

        $body.append('<div id="fvpp-blackout"></div>');
        $dialog.append('<a id="fvpp-close">&#10006;</a>');
        $blackout = $('#fvpp-blackout');

        if (getCookie('fvpp' + settings.cookieName)) {
            hideMessage();
        } else {
            showMessage();
        }

        $(settings.showAgainSelector).on('click', showMessage);
        $body.on('click', '#fvpp-blackout, #fvpp-close', hideMessage);

    };

})(jQuery);

Answer 1

更改:

date.setTime(date.getTime() + 31536000000);

至:

date.setDate(date.getDate() + 1);

这增加了1天的日期.旧代码增加了365天.