San*_*ndy 13 ui-testing ios xcode7 xcode-ui-testing
我的一个屏幕有多个文本字段,我可以从不同的其他屏幕登陆到这个屏幕.在每种情况下,我将一个或另一个文本字段作为第一响应者.我无法编写测试来确定所需的textField是否具有焦点.
当我在控制台中打印文本字段时 -
输出:{TextField 0x131171d40:traits:146031247360,Focused,{{ 6.0,108.3 },{402.0,35.0}},value:}
但我在XCUIElement上找不到任何focus/isFocus属性.
有没有办法实现这个目标?
hri*_*.to 23
我对派对来说有点迟了:)但是从转储变量XCUIElement可以看出它有一个有趣的属性:
属性名称:hasKeyboardFocus
物业类型:TB,R
因此,您可以通过以下方式检查元素是否具有焦点:
let hasFocus = (yourTextField.value(forKey: "hasKeyboardFocus") as? Bool) ?? false
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注意:您可以使用以下扩展名转储任何NSObject子类的属性变量:
extension NSObject {
func dumpProperties() {
var outCount: UInt32 = 0
let properties = class_copyPropertyList(self.dynamicType, &outCount)
for index in 0...outCount {
let property = properties[Int(index)]
if nil == property {
continue
}
if let propertyName = String.fromCString(property_getName(property)) {
print("property name: \(propertyName)")
}
if let propertyType = String.fromCString(property_getAttributes(property)) {
print("property type: \(propertyType)")
}
}
}
}
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更新:属性转储,Swift 4:*
extension NSObject {
func dumpProperties() {
var outCount: UInt32 = 0
let properties = class_copyPropertyList(type(of: self), &outCount)
for index in 0...outCount {
guard let property = properties?[Int(index)] else {
continue
}
let propertyName = String(cString: property_getName(property))
print("property name: \(propertyName)")
guard let propertyAttributes = property_getAttributes(property) else {
continue
}
let propertyType = String(cString: propertyAttributes)
print("property type: \(propertyType)")
}
}
}
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基于@ hris.to的出色回答,我整理了这个小扩展名(也可以在Swift 4中使用)...
extension XCUIElement
{
func hasFocus() -> Bool {
let hasKeyboardFocus = (self.value(forKey: "hasKeyboardFocus") as? Bool) ?? false
return hasKeyboardFocus
}
}
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