我用Swift 2.0编写代码.
我得到了这样的URL字符串:
let urlString = "http://example.com/api/getfile/?filepath=C:\\1.txt"
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当我将其转换为NSURL时,它返回nil.
let OrginUrl = NSURL(string: urlString)
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有人知道怎么做吗?
有两个问题需要解决:
为了包含\它必须进行转义,因为它本身就是转义字符.
URL中不允许使用'\'字符,因此需要对其进行URL编码
let urlString = "http://example.com/api/getfile/?filepath=C:\\\\1.txt"
print("urlString: \(urlString)")
var escapedString = urlString.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLHostAllowedCharacterSet())
print("escapedString!: \(escapedString!)")
let orginUrl = NSURL(string: escapedString!)
print("orginUrl: \(orginUrl!)")
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urlString:http://example.com/api/getfile/? filepath = C:\\\ ttxt
escapedString!:
http%3A%2F%2Fexample.com%2Fapi%2Fgetfile%2F%3Ffilepath = C%3A%5C%5C1.txtorginUrl:
http%3A%2F%2Fexample.com%2Fapi%2Fgetfile%2F%3Ffilepath = C%3A%5C%5C1.txt
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