在Ruby中,我需要将一个句子分成子句

Question

鉴于字符串:

"See Spot Run"

我需要返回一个数组:

[ "See", "Spot", "run", "See Spot", "Spot run", "See Spot Run" ]

到目前为止,我有:

term = "The cat sat on the mat"
#=> "The cat sat on the mat" 

arr = term.split(" ")
#=> ["The", "cat", "sat", "on", "the", "mat"] 

arr.length.times.map { |i| (arr.length - i).times.map { |j| arr[j..j+i].join(" ") } }.flatten(1)
#=> ["The", "cat", "sat", "on", "the", "mat", "The cat", "cat sat", "sat on", "on the", "the mat", "The cat sat", "cat sat on", "sat on the", "on the mat", "The cat sat on", "cat sat on the", "sat on the mat", "The cat sat on the", "cat sat on the mat", "The cat sat on the mat"] 

这种情况会发生很多次,所以你能想出一种提高效率的方法吗？

Answer 1

我each_cons在一个循环中使用:(虽然它不是更快)

arr = %w[The cat sat on the mat]
(1..arr.size).flat_map { |i| arr.each_cons(i).map { |words| words.join(' ') } }
#=> ["The", "cat", "sat", "on", "the", "mat",
#    "The cat", "cat sat", "sat on", "on the", "the mat",
#    "The cat sat", "cat sat on", "sat on the", "on the mat",
#    "The cat sat on", "cat sat on the", "sat on the mat",
#    "The cat sat on the", "cat sat on the mat",
#    "The cat sat on the mat"]