我是python的新手,所以我一直试图找出如何以下面的格式打印以下列表.我试图让它们通过索引但它似乎没有成功.
所以我有一个元组列表,我需要以下列格式打印出来:
1. A1 to B1
2. C1 to D2 , C1 to B2
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这是我需要转换为该格式的以下列表.
[['A1', 'B1'], ['C1', 'D2', 'C1', 'B2', 'C1', 'E3', 'C1', 'A3', 'C1', 'F4', 'C1', 'G5', 'C1', 'H6'], ['E1', 'D1', 'E1', 'F2', 'E1', 'D2', 'E1', 'G3', 'E1', 'H4']]
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>>> tuples = [['A1', 'B1'],
... ['C1', 'D2', 'C1', 'B2', 'C1', 'E3', 'C1', 'C2'],
... ['E1', 'D1', 'E1', 'F2']]
>>> for i, sequence in enumerate(tuples, 1):
... it = iter(sequence)
... print(i, ', '.join('{} to {}'.format(x, y) for x, y in zip(it, it))
1 A1 to B1
2 C1 to D2, C1 to B2, C1 to E3, C1 to C2
3 E1 to D1, E1 to F2
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如果列表中的元素数量为奇数zip(),itertools.izip_longest()则必须替换为:
>>> from itertools import izip_longest
>>> tuples = [['A1', 'B1', 'T1'],
['C1', 'D2', 'C1', 'B2', 'C1', 'E3', 'C1', 'C2', 'Z1'],
['E1', 'D1', 'E1', 'F2']]
>>> for i, sequence in enumerate(tuples, 1):
... it = iter(sequence)
... print(i, ', '.join('{} to {}'.format(x, y)
... for x, y in izip_longest(it, it, fillvalue='X'))
1 A1 to B1, T1 to X
2 C1 to D2, C1 to B2, C1 to E3, C1 to C2, Z1 to X
3 E1 to D1, E1 to F2
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