Python lambda函数打印<function <lambda>在0x7fcbbc740668>而不是值

Question

我是python的初学者,我正在玩lambda函数.我正在编写一个程序,使用lambda函数来打印输入字符的ascii值为+1的字符.我的代码是

#!/usr/bin/python
import sys
try:
  word = sys.argv[1]
except:
  print "No arguments passed"
  sys.exit(1)

def convert_ascii(char):
  return  "".join(chr(ord(char) + 1))

for i in word:
  print convert_ascii(i)
  print lambda x: chr(ord(i) + 1)

我有一个函数convert_ascii,它与lambda做同样的事情.但是,我的输出是

/usr/bin/python2.7 /home/user1/PycharmProjects/test/Tut1/asciipl2.py "abc def ghi"
b
<function <lambda> at 0x7f0310160668>
c
<function <lambda> at 0x7f0310160668>
d
<function <lambda> at 0x7f0310160668>
!
<function <lambda> at 0x7f0310160668>
e
<function <lambda> at 0x7f0310160668>
f
<function <lambda> at 0x7f0310160668>
g
<function <lambda> at 0x7f0310160668>
!
<function <lambda> at 0x7f0310160668>
h
<function <lambda> at 0x7f0310160668>
i
<function <lambda> at 0x7f0310160668>
j
<function <lambda> at 0x7f0310160668>

这个脚本的目的是学习lambda,虽然还有其他方法可以做这个程序.请让我知道我做错了什么.进程以退出代码0结束

Answer 1

你没有调用这个函数.这和你写的一样, print convert_ascii而不是print convert_ascii(i).

尝试

print (lambda x: chr(ord(x) + 1))(i)

请注意,我在函数体中更改ord(i)为ord(x).