如何将相同的数据存储在两个不同的mySQL表中?

pea*_*ove 1 php sql

当新客户购买产品时,我想将客户端详细信息存储在clients表中,并将相应的client_ID存储在orders表中.

订单表:

order_ID   product   client   
============================
 1501      bag         1
 1502      shoe        2  
Run Code Online (Sandbox Code Playgroud)

客户表:

client_ID   name      
=================
   1       Frank         
   2       John   
Run Code Online (Sandbox Code Playgroud)

我找到了一个有效的解决方案,但我觉得,这不是最聪明的解决方案.

$sql = "INSERT INTO clients(name) VALUES(?)";
$q = $con->prepare($sql);
$q->execute(array($name));

$sql = "INSERT INTO orders(product) VALUES(?)";
$q = $con->prepare($sql);
$q->execute(array($product));

$sql = 'SELECT * FROM clients ORDER BY client_ID DESC LIMIT 0, 1';
foreach ($con->query($sql) as $row) {
    $client = $row['client'];
    $sql = "UPDATE orders SET client = '$client' WHERE client IS NULL";
    $query = $con->prepare($sql);
    $query->execute();
}
Run Code Online (Sandbox Code Playgroud)

我的问题是,有更好的方法吗?(备注:client_ID为AUTO_INCREMENT)

小智 6

获取插入数据库的最后一个id:

$sql = "INSERT INTO clients(name) VALUES(?)";
$q = $con->prepare($sql);
$q->execute(array($name)); 

// Assuming you use PDO:
$clientId = $con->lastInsertId();

// For mysqli this would be:
// $clientId = $con->insert_id;


$sql = "INSERT INTO orders(product, client) VALUES(?, ?)";
$q = $con->prepare($sql);
$q->execute(array($product, $clientID)); 
Run Code Online (Sandbox Code Playgroud)