Gui*_*ira 3 android json okhttp
private static final String URL = "http://www.livroandroid.com.br/livro/carros/carros_{tipo}.json";
public static List<Carro> getCarros(Context context, String tipo) throws IOException {
String url = URL.replace("{tipo}", tipo);
OkHttpClient okHttpClient = new OkHttpClient();
Request request = new Request.Builder()
.url(URL)
.build();
Response response = okHttpClient.newCall(request).execute();
String json = response.body().toString();
List<Carro> carros = parserJSON(context, json);
return carros;
}
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如果我json在调用getCarros方法时打印出变量的值,我在logcat中看到以下消息:
com.squareup.okhttp.internal.http.RealResponseBody@1e11866
如何记录我收到的实际JSON字符串?
stk*_*ent 20
(最初回答OkHttp版本2.5.0).
更换
String json = response.body().toString();
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同
String json = response.body().string();
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response.body返回一个ResponseBody对象,它有自己的string方法:在这里查看源代码.
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