ORACLE 10.2 Pro*C预编译器没有读取头文件

Question

我正在使用Oracle 10.2和AIX 5.2预编译包含Pro*C代码的C程序

Oracle预编译器读取$ORACLE_HOME/precomp/admin/pcscfg.cfg file包含sys_include变量定义(设置为/usr/include)的内容.

Pro*C编译器抱怨它不知道size_t类型是什么,并且使用该size_t类型的Oracle头文件报告错误.

这是在sqlcpr.h文件上报告的示例错误:

extern void sqlglm( char*, size_t*, size_t* );
...........................1
PCC-S-02201, Encountered the symbol "size_t" when expecting one of the following

size_tstdio.h在/usr/include目录的头文件中定义.我包括stdio.h我的头example.pc文件之前包括我的sqlcpr.h头.

我发出proc命令如下:

proc iname=example parse=full

我有什么想法我做错了吗？

Answer 1

来自Metalink

PCC-S-02201, Encountered the symbol "size_t" when expecting one of the 
following
:
   ... auto, char, const, double, enum,  float, int, long,
   ulong_varchar, OCIBFileLocator OCIBlobLocator,
   OCIClobLocator, OCIDateTime, OCIExtProcContext, OCIInterval,
   OCIRowid, OCIDate, OCINumber, OCIRaw, OCIString, register,
   short, signed, sql_context, sql_cursor, static, struct,
   union, unsigned, utext, uvarchar, varchar, void, volatile,
   a typedef name, exec oracle, exec oracle begin, exec,
   exec sql, exec sql begin, exec sql type, exec sql var,
The symbol "enum," was substituted for "size_t" to continue.
Syntax error at line 88, column 7, file /usr/include/gconv.h:
Error at line 88, column 7 in file /usr/include/gconv.h
                                  size_t *);

解决方案描述

'sys_include'和'include'预编译器选项未正确设置. 在$ ORACLE_HOME/precomp/admin的pcscfg.cfg文件中设置'sys_include'和'include'预编译器选项,或在调用'proc'时在命令行中包含.

例如,以下是正确设置变量的推荐方法:

运行以下命令以获取编译器位置:

gcc -v

阅读/usr/lib/gcc-lib/i386-redhat-linux7/2.96/specs gcc版本2.96 20000731(Red Hat Linux 7.3 2.96-128)中的规范

使用上面返回的路径(删除规范并用include替换)

sys_include=($ORACLE_HOME/precomp/public,
             /usr/lib/gcc-lib/i386-redhat-linux7/2.96/include, 
             /usr/include)

include=(/u02/app/oracle/product/8.1.5/precomp/public)
include=(/u02/app/oracle/product/8.1.5/rdbms/demo)
include=(/u02/app/oracle/product/8.1.5/network/public)
include=(/u02/app/oracle/product/8.1.5/plsql/public)

我猜测同时包含sysinclude和include的部分是你的问题.