在一些R函数的主体中,例如lm我看到对match.call函数的调用.正如帮助页面所说,在函数内部使用时会match.call返回一个调用,其中指定了参数名称; 这对于将大量参数传递给另一个函数应该是有用的.
例如,在lm函数中我们看到对函数的调用model.frame
function (formula, data, subset, weights, na.action, method = "qr",
model = TRUE, x = FALSE, y = FALSE, qr = TRUE, singular.ok = TRUE,
contrasts = NULL, offset, ...)
{
cl <- match.call()
mf <- match.call(expand.dots = FALSE)
m <- match(c("formula", "data", "subset", "weights", "na.action",
"offset"), names(mf), 0L)
mf <- mf[c(1L, m)]
mf$drop.unused.levels <- TRUE
mf[[1L]] <- quote(stats::model.frame)
mf <- eval(mf, parent.frame())
...
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为什么这比直接调用model.frame指定参数名称更有用呢?
function (formula, data, subset, weights, na.action, method = "qr",
model = TRUE, x = FALSE, y = FALSE, qr = TRUE, singular.ok = TRUE,
contrasts = NULL, offset, ...)
{
mf <- model.frame(formula = formula, data = data,
subset = subset, weights = weights, subset = subset)
...
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请注意,match.call我没有讨论另一个用途,将调用存储在结果对象中.
与此相关的一个原因是,match.call在不对其进行评估的情况下捕获调用的语言,并且在这种情况下,它允许lm将一些"缺失"变量视为"可选".考虑:
lm(x ~ y, data.frame(x=1:10, y=runif(10)))
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VS:
lm2 <- function (
formula, data, subset, weights, na.action, method = "qr",
model = TRUE, x = FALSE, y = FALSE, qr = TRUE, singular.ok = TRUE,
contrasts = NULL, offset, ...
) {
mf <- model.frame(
formula = formula, data = data, subset = subset, weights = weights
)
}
lm2(x ~ y, data.frame(x=1:10, y=runif(10)))
## Error in model.frame.default(formula = formula, data = data, subset = subset, :
## invalid type (closure) for variable '(weights)'
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在lm2,因为weights"缺失",但你仍然使用它weights=weights,R尝试使用stats::weights明显不是预期的功能.你可以通过在打电话之前测试缺失来解决这个问题model.frame,但在那时match.call开始看起来很不错.看看如果我们debug打电话会发生什么:
debug(lm2)
lm2(x ~ y, data.frame(x=1:10, y=runif(10)))
## debugging in: lm2(x ~ y, data.frame(x = 1:10, y = runif(10)))
## debug at #5: {
## mf <- model.frame(formula = formula, data = data, subset = subset,
## weights = weights)
## }
Browse[2]> match.call()
## lm2(formula = x ~ y, data = data.frame(x = 1:10, y = runif(10)))
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match.call 根本不涉及缺失的论点.
您可以争辩说,可选参数应该通过默认值显式选择,但这不是这里发生的事情.
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