将固定长度数转换为十进制.NET C#

Question

我有一个导入的txt文件,其格式为:

00000000003000
00000000009500
00000000003000
00000000002000
00000000000500-
00000000001500-
00000000003000-
00000000003000-
00000000009500-

这是最后2个字符为小数的数字.(如果为负值则减号)例如:

00000000003000 = 30.00
00000000000500- = -5.00

是否有一个函数将此字符串转换为十进制并节省我的时间写一个？

谢谢.

Answer 1

试试这个:

 String source = "00000000001500-";

 Decimal result = Decimal.Parse(source, 
   NumberStyles.Any, // NumberStyles.Any includes trailing signs
   CultureInfo.InvariantCulture) / 100.0M;

如果你想(对某些字段,值)4位小数只是改变100.0M对10000.0M这些字段:

 Decimal result4 = Decimal.Parse(source, 
   NumberStyles.Any, // NumberStyles.Any includes trailing signs
   CultureInfo.InvariantCulture) / 10000.0M;