Java:ArrayList给出了一个乱码的结果

Question

问题如下:屏幕上显示6个字.这些单词是从列表中随机选择的.当我编写代码时,我没有收到任何错误,但是当我在eclipse中运行它时,我在控制台"package.wordsContainer@659e0bfd"中得到了以下乱码结果.

我做错了什么？

public class wordsContainer {
    Collection<String> wordList = new ArrayList<String>();

    public void wordGroup1() {
        wordList.add("Ant");
        wordList.add("Almond");
        wordList.add("Atom");
        wordList.add("Affair");
        wordList.add("Ample");
        wordList.add("Blue");
        wordList.add("Black");
        wordList.add("Bronze");
        wordList.add("Beauty");
        wordList.add("Beautiful");
        wordList.add("Batter");
        wordList.add("Crazy");
    }


    public Collection<String> getRandomWords() {
        wordGroup1();
        LinkedList<String> wordLinkedList = new LinkedList<String>(wordList);
        ArrayList<String> subList = new ArrayList<String>();

        int i = 0;
        while (i < 6) {
            int index = (int) Math.random() * 10;
            if (!subList.contains(wordLinkedList.get(index))) {
                subList.add(wordLinkedList.get(index));
                i++;
            }
        }
        return subList;
    }
}



public class wordsContainerTest {
    public static void main(String[] args) {
        wordsContainer list1 = new wordsContainer();

        list1.wordGroup1();

        System.out.println(list1);
        System.out.println(list1.getRandomWords());

    }
}

Answer 1

它不是对象哈希码的乱码,十六进制表示 wordsContainer

结果来自这条线

   System.out.println(list1); //wordsContainer 

不是来自ArrayList.

为了正常工作,您需要在类中重写toString方法 wordsContainer

为了理解究竟是什么 "package.wordsContainer@659e0bfd" ,我回答了很久以前写的答案.

/sf/answers/1251494681/

除此之外,请遵循java命名约定,类名以大写字母开头.