Kee*_*ong 16 python enums metaprogramming metaclass
我一直在搞乱python的枚举库,并遇到了一个难题.在文档中,它们显示了一个自动编号枚举的示例,其中定义了一些内容:
class Color(AutoNumber):
red = ()
green = ()
...
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我想创建一个类似的类,但是该值将自动从成员的名称设置并保留从执行str和mixin中获得的功能enum
所以类似于:
class Animal(MagicStrEnum):
horse = ()
dog = ()
Animal.dog == 'dog' # True
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我已经查看了枚举模块的源代码,并尝试了很多变化__new__和EnumMeta类
Eth*_*man 16
更新:2017-03-01
在Python 3.6(和1)和类已添加; 其中一部分是一个新的帮手,使这个简单易行:
Aenum 2.0FlagIntFlagauto()
>>> class AutoName(Enum):
... def _generate_next_value_(name, start, count, last_values):
... return name
...
>>> class Ordinal(AutoName):
... NORTH = auto()
... SOUTH = auto()
... EAST = auto()
... WEST = auto()
...
>>> list(Ordinal)
[<Ordinal.NORTH: 'NORTH'>, <Ordinal.SOUTH: 'SOUTH'>, <Ordinal.EAST: 'EAST'>, <Ordinal.WEST: 'WEST'>]
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原始答案
AutoStr类的难点在于枚举成员的名称未传递给创建它的代码,因此无法使用.另一个问题是str不可变的,所以我们不能在创建它们之后更改这些类型的枚举(例如,通过使用类装饰器).
最简单的方法是使用Functional API:
Animal = Enum('Animal', [(a, a) for a in ('horse', 'dog')], type=str)
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这给了我们:
>>> list(Animal)
[<Animal.horse: 'horse'>, <Animal.dog: 'dog'>]
>>> Animal.dog == 'dog'
True
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下一个最简单的事情,假设你想为将来的枚举使用创建一个基类,就像我的DocEnem:
class DocEnum(Enum):
"""
compares equal to all cased versions of its name
accepts a doctring for each member
"""
def __new__(cls, *args):
"""Ignores arguments (will be handled in __init__)"""
obj = object.__new__(cls)
obj._value_ = None
return obj
def __init__(self, doc=None):
# first, fix _value_
self._value_ = self._name_.lower()
self.__doc__ = doc
def __eq__(self, other):
if isinstance(other, basestring):
return self._value_ == other.lower()
elif not isinstance(other, self.__class__):
return NotImplemented
return self is other
def __hash__(self):
# keep DocEnum hashable
return hash(self._value_)
def __ne__(self, other):
return not self == other
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并在使用中:
class SpecKind(DocEnum):
REQUIRED = "required value"
OPTION = "single value per name"
MULTI = "multiple values per name (list form)"
FLAG = "boolean value per name"
KEYWORD = 'unknown options'
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请注意,与第一个选项不同,DocEnum成员不是 str s.
如果你想以艰难的方式去做:在创建成员之前创建EnumMeta新Enum的类字典的子类和小提琴:
from enum import EnumMeta, Enum, _EnumDict
class StrEnumMeta(EnumMeta):
def __new__(metacls, cls, bases, oldclassdict):
"""
Scan through `oldclassdict` and convert any value that is a plain tuple
into a `str` of the name instead
"""
newclassdict = _EnumDict()
for k, v in oldclassdict.items():
if v == ():
v = k
newclassdict[k] = v
return super().__new__(metacls, cls, bases, newclassdict)
class AutoStrEnum(str, Enum, metaclass=StrEnumMeta):
"base class for name=value str enums"
class Animal(AutoStrEnum):
horse = ()
dog = ()
whale = ()
print(Animal.horse)
print(Animal.horse == 'horse')
print(Animal.horse.name, Animal.horse.value)
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这给了我们:
Animal.horse
True
horse horse
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1披露:我是Python stdlibEnum,enum34backport和Advanced Enumeration(aenum) 库的作者.
也许您正在寻找类name自动提供的属性Enum
>>> class Animal(Enum):
... ant = 1
... bee = 2
... cat = 3
... dog = 4
...
>>> Animal.ant.name == "ant"
True
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但如果你真的想搬起石头砸自己的脚。我确信这会带来一大堆陷阱(我已经消除了最明显的一个)。
from enum import Enum, EnumMeta, _EnumDict
class AutoStrEnumDict(_EnumDict):
def __setitem__(self, key, value):
super().__setitem__(key, key)
class AutoStrEnumMeta(EnumMeta):
@classmethod
def __prepare__(metacls, cls, bases):
return AutoStrEnumDict()
def __init__(self, name, bases, attrs):
super().__init__(name, bases, attrs)
# override Enum.__str__
# can't put these on the class directly otherwise EnumMeta overwrites them
# should also consider resetting __repr__, __format__ and __reduce_ex__
if self.__str__ is not str.__str__:
self.__str__ = str.__str__
class AutoStrNameEnum(str, Enum, metaclass=AutoStrEnumMeta):
pass
class Animal(AutoStrNameEnum):
horse = ()
dog = ()
print(Animal.horse)
assert Animal.horse == "horse"
assert str(Animal.horse) == "horse"
# and not equal to "Animal.horse" (the gotcha mentioned earlier)
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