Url.Action()导致System.AccessViolationException

Question

我在标准的ASP.NET MVC项目中向ASP.NET身份模型添加了电子邮件验证.以下行导致AccessViolationException:

callbackUrl = Url.Action("ConfirmEmail", "Account", confirmModel, Request.Url.Scheme);

更新: 由于问题无法解释,它就消失了.我会试着弄清楚是什么让它消失了.令我担心的是,我不知道解决方案有任何重大变化.

用于注册用户的完整帐户控制器方法如下所示:

// POST: /Account/Register
[HttpPost]
[AllowAnonymous]
[ValidateAntiForgeryToken]
public async Task<ActionResult> Register(RegisterViewModel model)
{
    if (ModelState.IsValid)
    {
        ApplicationUser user = new ApplicationUser { UserName = model.Email, Email = model.Email };
        IdentityResult result = await UserManager.CreateAsync(user, model.Password);
        if (result.Succeeded)
        {
            string code = await UserManager.GenerateEmailConfirmationTokenAsync(user.Id);

            string callbackUrl;
            try
            {
                string requestScheme = Request.Url.Scheme;
                object confirmModel = new { userId = user.Id, code = code };
                callbackUrl = Url.Action("ConfirmEmail", "Account", confirmModel, Request.Url.Scheme); // TODO: Fails somehow!
            }
            catch (Exception ex)
            {
                Debug.WriteLine(ex);
                callbackUrl = "https://localhost:43000/Account/ConfirmEmail?userid=" + user.Id + "&code=" + code;
            }

            await
                UserManager.SendEmailAsync(
                        userId: user.Id,
                        subject: "Verify it's you",
                        body: "Please confirm your email address by clicking <a href=\"" + callbackUrl + "\">here</a>");

            return View("CheckYourEmail");
        }

        AddErrors(result);
    }

    // If we got this far, something failed, redisplay form
    return View(model);
}

不幸的是,没有内部异常或任何有用的东西.

catch()块作为一种解决方法解决了这个问题.
但我真的很好奇这里出了什么问题.

Answer 1

不要将其设置为 object recognizeModel = ...，而是使用“dynamic recognizeModel = ...”并查看是否可以解决该问题。