jhe*_*dus 2 python numpy scipy correlation
我使用numpy的关联函数得到以下结果:
In [153]: np.correlate([1],np.arange(100))
Out[153]:
array([99, 98, 97, 96, 95, 94, 93, 92, 91, 90, 89, 88, 87, 86, 85, 84, 83,
82, 81, 80, 79, 78, 77, 76, 75, 74, 73, 72, 71, 70, 69, 68, 67, 66,
65, 64, 63, 62, 61, 60, 59, 58, 57, 56, 55, 54, 53, 52, 51, 50, 49,
48, 47, 46, 45, 44, 43, 42, 41, 40, 39, 38, 37, 36, 35, 34, 33, 32,
31, 30, 29, 28, 27, 26, 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15,
14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0])
In [154]:
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这个结果似乎与numpy 书的90页相矛盾:
基于上面的公式,我预计会增加数组0..99,但结果是减少数组99..0.
有人能解释一下这里发生了什么吗?
为什么实施与规范相矛盾?
为什么颠倒列表是有意义的?
看起来你期待的old_behaviour是numpy.correlate.你链接到的书很旧(2006年),所以看起来它numpy.correlate已经改变了(因为它已被改写numpy v1.4).来自以下文档numpy v1.9:
old_behavior:布尔
如果为True,则使用Numeric中的旧行为,(correlate(a,v)== correlate(v,a),并且不对复杂数组采用共轭).如果为False,则使用传统的信号处理定义.
In [2]: np.correlate([1],np.arange(100))
Out[2]:
array([99, 98, 97, 96, 95, 94, 93, 92, 91, 90, 89, 88, 87, 86, 85, 84, 83,
82, 81, 80, 79, 78, 77, 76, 75, 74, 73, 72, 71, 70, 69, 68, 67, 66,
65, 64, 63, 62, 61, 60, 59, 58, 57, 56, 55, 54, 53, 52, 51, 50, 49,
48, 47, 46, 45, 44, 43, 42, 41, 40, 39, 38, 37, 36, 35, 34, 33, 32,
31, 30, 29, 28, 27, 26, 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15,
14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0])
In [3]: np.correlate([1],np.arange(100),old_behavior=True)
Out[3]:
array([ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16,
17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33,
34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50,
51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67,
68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84,
85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99])
In [4]: np.correlate(np.arange(100),[1])
Out[4]:
array([ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16,
17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33,
34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50,
51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67,
68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84,
85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99])
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编辑
在进一步检查时,我认为差异是由于旧定义中的这一行:
K=len(x)-1并且M=len(y)-1,我们假设K ? M(不失一般性,因为我们可以互换角色x和y没有影响).
所以,我相信,你的情况下,在旧的定义,它正在y=[1]和x=np.arange(100),因为len(x)必须大于len(y).新定义不会这样做,而是"输入数组从不交换",所以x=[1]和y=np.arange(100).因此,差异.
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