如何在Yii2 gridview中连接两个表并获取值

Question

我正在使用Yii2 gridview小部件来显示数据.

我正在使用两个名为message和message_trigger的表.

在消息表列中object_model,Object_id.

在message_trigger中,列是object_id,object_name.

网格从表消息中获取值.所以网格字段是Object_model,Object_id.

现在我的问题是我需要表现出Object_name从表格message_trigger基础上,object_id从表中的消息.

在我的形式中,我使用了这样的网格

<?= GridView::widget([
    'dataProvider' => $dataProvider,
    'filterModel' => $searchModel,
    'columns' => [
        ['class' => 'yii\grid\SerialColumn'],
        'object_model',
        'object_id',
        ['class' => 'yii\grid\ActionColumn', 'template' => '{view} {update} {delete} '],
    ],
]); ?>

在我使用过的模型中

public function search($params){
    $query = AlertTrigger::find()->where(['alert_id'=>$params['id']])->andWhere(['!=','status',2]);
    $dataProvider = new ActiveDataProvider([
        'query' => $query,
    ]);
}

Answer 1

在Message模型中

public function getMessageTrigger()
{
    return $this->hasOne(MessageTrigger::className(), ['object_id' => 'object_id']);
}

在视野中

<?= GridView::widget([
    'dataProvider' => $dataProvider,
    'filterModel' => $searchModel,
    'columns' => [
        ['class' => 'yii\grid\SerialColumn'],
        'object_model',
        'object_id',
        [
            'label' => 'Name',
            'value' => 'messageTrigger.object_name',
        ],
        ['class' => 'yii\grid\ActionColumn', 'template' => '{view} {update} {delete} '],
    ],
]); ?>