单击时UITextView不打开URL

Question

我有一个UITextView里面有一个属性字符串,其中包含一个URL.属性字符串正在转换为链接,但是当您按下链接时会出现错误:

未知DDResult类别1的结果; 找不到网址www.myurl.com的任何操作

这是我的代码:

NSMutableAttributedString * str = [[NSMutableAttributedString alloc] initWithString:NSLocalizedString(@"My Text", nil)];
NSRange range = [str.mutableString rangeOfString:@"www.myurl.com" options:NSCaseInsensitiveSearch];

if (range.location != NSNotFound) {
    [str addAttribute:NSFontAttributeName value:[UIFont fontWithName:@"CourierPrime-Bold" size:15] range:NSMakeRange(0, range.location)];
    [str addAttribute:NSLinkAttributeName value:[NSURL URLWithString:@"www.myurl.com"] range:range];
    [str addAttribute:NSForegroundColorAttributeName value:[UIColor brownColor] range:range];
}


self.welcomeText.editable = NO; 
self.welcomeText.attributedText = str;

//As a note, I have tried this with the value 0 and UIDataDetectorTypeLink
//and neither option worked.
self.welcomeText.dataDetectorTypes = UIDataDetectorTypeAll;

我正在使用XIB和我已selectable启用的行为选项,以及我links选择的检测选项.

我想在可能的情况下在手机移动浏览器中打开链接,而不是创建webview.

Answer 1

URL需要一个方案.

这个:

[str addAttribute:NSLinkAttributeName value:[NSURL URLWithString:@"www.myurl.com"] range:range];

需要是:

[str addAttribute:NSLinkAttributeName value:[NSURL URLWithString:@"http://www.myurl.com"] range:range];