我正在做一些简单的事情,所以希望这个问题很容易回答.我正在使用gcc进行编译.推动效果非常好.问题是流行音乐.每当我编译并运行它时,我都会遇到分段错误.
以下是pop和push功能:
int push(stack *stk, int data)
{
stk->head = makeNode(data, stk->head);
stk->length += 1;
return data;
}
int pop(stack *stk)
{
//Returns popped item
//Returns -1 if stack length is zero
if (stk->length < 1)
{
printf("No items to pop.");
return -1;
}
int data = stk->head->value;
struct node *toBeFreed = stk->head;
stk->head = stk->head->ptr;
free(toBeFreed);
stk->length -= 1;
return data;
}
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老实说,我不知道问题是什么,因为代码是相似的.我在push函数中重新分配堆栈中的head变量,但它会导致pop函数出错.对数据的分配也给了我一个seg错误.除了返回和堆栈长度赋值语句之外,几乎所有内容都会给出分段错误.你们任何人都可以帮我解决这个问题吗?造成这些seg故障的原因是什么?
这是整个计划:
#include <stdio.h>
#include <stdlib.h>
struct node
{
int value;
struct node *ptr;
};
struct node *makeNode(int value, struct node *ptr)
{
struct node *newNode = malloc(sizeof(struct node));
newNode->value = value;
newNode->ptr = ptr;
return ptr;
}
typedef struct stack
{
struct node *head;
int length;
} stack;
stack makeStack()
{
stack stk;
stk.head=NULL;
stk.length = 0;
return stk;
}
int push(stack *stk, int data)
{
stk->head = makeNode(data, stk->head);
stk->length += 1;
return data;
}
int pop(stack *stk)
{
if (stk->length < 1)
{
printf("No items to pop.");
return -1;
}
int data = stk->head->value;
struct node *toBeFreed = stk->head;
stk->head = stk->head->ptr;
free(toBeFreed);
stk->length -= 1;
return data;
}
int main()
{
stack s = makeStack();
printf("Pushing ints one through five. Should display ints one through five on separate lines: \n");
int i;
for (i = 1; i <= 5; i++)
printf("%d\n",push(&s, i));
printf("Popping ten values. Should display ints one through five in reverse order on separate lines along with 5 error statements.\n");
for (i = 0; i <= 10; i++)
printf("%d\n",pop(&s));
return 0;
}
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struct node *makeNode(int value, struct node *ptr)
{
struct node *newNode = malloc(sizeof(struct node));
newNode->value = value;
newNode->ptr = ptr;
return ptr;
}
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你想回来newNode,而不是ptr.
你得到段错误的原因是,由于makeNode错误堆栈将保持为空,但是size将增至5,所以当你pop的栈不知道这是空的,它试图取消引用空指针.
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