我正在尝试在Rust中实现一个Octree.八叉树在具有约束的类型上是通用的,它应该实现一般特征:
pub trait Generable<U> {
fn generate_children(&self, data: &U) -> Vec<Option<Self>>;
}
pub enum Octree<T, U>
where
T: Generable<U>,
{
Node {
data: T,
children: Vec<Box<Octree<T, U>>>,
},
Empty,
Uninitialized,
}
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这会产生错误:
error[E0392]: parameter `U` is never used
--> src/main.rs:5:20
|
5 | pub enum Octree<T, U>
| ^ unused type parameter
|
= help: consider removing `U` or using a marker such as `std::marker::PhantomData`
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U从签名中删除会导致"未声明的类型名称'U'".
我做错了什么还是错误?怎么做得好?
我不相信你想要另一个通用,你想要一个相关的类型:
pub trait Generable {
type From;
fn generate_children(&self, data: &Self::From) -> Vec<Option<Self>>
where
Self: Sized;
}
pub enum Octree<T>
where
T: Generable,
{
Node {
data: T,
children: Vec<Box<Octree<T>>>,
},
Empty,
Uninitialized,
}
fn main() {}
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顺便说一句,Vec<Box<Octree<T>>>可能只有一个额外的间接 - 你可以使用Vec<Octree<T>>.
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