rap*_*ael 8 arrays json postgresql-9.3
我正在从JSON中的API中提取数据,其格式类似于下面的示例数据.基本上每个"行"都是一个值数组.API文档提前定义列及其类型.所以我知道col1是一个varchar,而col2是一个int.
CREATE TEMP TABLE dat (data json);
INSERT INTO dat
VALUES ('{"COLUMNS":["col1","col2"],"DATA":[["a","1"],["b","2"]]}');
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我想在PostgreSQL 9.3中对此进行转换,以便最终得到:
col1 | col2
------------
a | 1
b | 2
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使用json_array_elements我可以到达:
SELECT json_array_elements(data->'DATA')
FROM dat
json_array_elements
json
---------
["a","1"]
["b","2"]
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但后来我无法弄清楚如何将JSON数组转换为PostgreSQL数组,以便我可以执行类似的操作 unnest(ARRAY['a','1'])
得到一个像这样的结果
col1 | col2
------------
a | 1
b | 2
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将需要一堆动态SQL,因为您事先不知道列的类型,也不知道列名.
您可以使用以下内容解压缩json:
SELECT
json_array_element_text(colnames, colno) AS colname,
json_array_element_text(colvalues, colno) AS colvalue,
rn,
idx,
colno
FROM (
SELECT
data -> 'COLUMNS' AS colnames,
d AS colvalues,
rn,
row_number() OVER () AS idx
FROM (
SELECT data, row_number() OVER () AS rn FROM dat
) numbered
cross join json_array_elements(numbered.data -> 'DATA') d
) elements
cross join generate_series(0, json_array_length(colnames) - 1) colno;
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生成如下结果集:
colname | colvalue | rn | idx | colno
---------+----------+----+-----+-------
col1 | a | 1 | 1 | 0
col2 | 1 | 1 | 1 | 1
col1 | b | 1 | 2 | 0
col2 | 2 | 1 | 2 | 1
(4 rows)
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然后,您可以使用此作为tablefunc模块的交叉表函数的输入,例如:
SELECT * FROM crosstab('
SELECT
to_char(rn,''00000000'')||''_''||to_char(idx,''00000000'') AS rowid,
json_array_element_text(colnames, colno) AS colname,
json_array_element_text(colvalues, colno) AS colvalue
FROM (
SELECT
data -> ''COLUMNS'' AS colnames,
d AS colvalues,
rn,
row_number() OVER () AS idx
FROM (
SELECT data, row_number() OVER () AS rn FROM dat
) numbered
cross join json_array_elements(numbered.data -> ''DATA'') d
) elements
cross join generate_series(0, json_array_length(colnames) - 1) colno;
') results(rowid text, col1 text, col2 text);
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生产:
rowid | col1 | col2
---------------------+------+------
00000001_ 00000001 | a | 1
00000001_ 00000002 | b | 2
(2 rows)
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列名称不会保留在此处.
如果你在9.4,你可以避免row_number()通话和使用WITH ORDINALITY,使它更清洁.
由于您显然事先知道了列数及其类型,因此可以大大简化查询.
SELECT
col1, col2
FROM (
SELECT
rn,
row_number() OVER () AS idx,
elem ->> 0 AS col1,
elem ->> 1 :: integer AS col2
FROM (
SELECT data, row_number() OVER () AS rn FROM dat
) numbered
cross join json_array_elements(numbered.data -> 'DATA') elem
ORDER BY 1, 2
) x;
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结果:
col1 | col2
------+------
a | 1
b | 2
(2 rows)
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WITH ORDINALITY如果您使用的是9.4,可以使用WITH ORDINALITY以下方法保持清洁:
SELECT
col1, col2
FROM (
SELECT
elem ->> 0 AS col1,
elem ->> 1 :: integer AS col2
FROM
dat
CROSS JOIN
json_array_elements(dat.data -> 'DATA') WITH ORDINALITY AS elements(elem, idx)
ORDER BY idx
) x;
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