使用akka-http时如何在另一个actor中完成请求

Question

我正在使用akka-http 1.0,我想使用定义为的路由

def route: Route = path("") {
  // start actor with requestContext
  // call requestContext.complete(...) in actor with the result
}

我该如何做到这一点？

Answer 1

在阐述@jrudolph的注释时,下面的代码满足了将RequestContext值分派给Actor的要求.您的问题表明您希望每个请求都有一个新的Actor; 但是,下面的代码对所有请求使用相同的Actor,我认为这是一个更有效/可能的用例.如果需要,可以始终在handleRequest内移动Actor创建.

首先,我们需要一个Actor来处理对响应的请求:

import akka.actor.Actor
import akka.http.scaladsl.server.{RequestContext, RouteResult}
import akka.http.scaladsl.model.HttpResponse

class RequestActor extends Actor {

  //business logic - returns empty HttpResponse
  def handleRequestMessage(requestContext : RequestContext) = 
    RouteResult.Complete(new HttpResponse())

  override def receive = {
    case reqContext : RequestContext => 
      sender ! handleRequestMessage(reqContext)
  }
}//end class RequestActor

现在创建一个用于查询Actor的实用程序函数:

import akka.actor.ActorRef
import scala.concurrent.Future
import akka.pattern.ask

object RequestActor {
  val handleRequest : ActorRef => RequestContext => Future[RouteResult] =
    (actorRef) =>
      (requestContext) =>
        ask(actorRef,reqContext).mapTo[RouteResult]
}

剩下要做的就是将所有内容连接成一个服务:

import akka.actor.{ActorSystem, Props}
import akka.stream.ActorMaterializer
import akka.http.scaladsl.Http
import akka.http.scaladsl.server.Directives.{get,path}
import akka.util.Timeout

object RouteActorTest extends App {
  implicit val as = ActorSystem("RouteActorTest")
  implicit val timeout = new Timeout(1000)

  val sendRequestToActor : RequestContext => Future[RouteResult] = 
    RequestActor handleRequest (as actorOf Props[RequestActor])      

  val route = path("")(get(sendRequestToActor))

  //rest of application...

}//end object RouteActorTest