Lombok我们可以将@Builder和@Value一起用于单个类

Question

首先感谢Lombok,我们的Java代码现在更加流畅和清洁.我的用例是我想创建一个不可变的类.为此我会使用@Value注释.另外我想使用构建器功能,因为我会使用@Builder注释.我的问题是,如果我们可以在一个类上同时使用@Builder和@Value.这是Lombok用户/开发人员推荐的好习惯.

Answer 1

当然可以.要检查,只需简化代码并查看它生成的内容.举个例子:

@Builder
@Value
public class Pair {
    private Object left;
    private Object right;
}

在delombokification之后,这产生:

public class Pair {
    private Object left;
    private Object right;

    @java.beans.ConstructorProperties({ "left", "right" })
    Pair(Object left, Object right) {
        this.left = left;
        this.right = right;
    }

    public static PairBuilder builder() {
        return new PairBuilder();
    }

    public Object getLeft() {
        return this.left;
    }

    public Object getRight() {
        return this.right;
    }

    public boolean equals(Object o) {
        if (o == this) return true;
        if (!(o instanceof Pair)) return false;
        final Pair other = (Pair) o;
        final Object this$left = this.left;
        final Object other$left = other.left;
        if (this$left == null ? other$left != null : !this$left.equals(other$left)) return false;
        final Object this$right = this.right;
        final Object other$right = other.right;
        if (this$right == null ? other$right != null : !this$right.equals(other$right)) return false;
        return true;
    }

    public int hashCode() {
        final int PRIME = 59;
        int result = 1;
        final Object $left = this.left;
        result = result * PRIME + ($left == null ? 0 : $left.hashCode());
        final Object $right = this.right;
        result = result * PRIME + ($right == null ? 0 : $right.hashCode());
        return result;
    }

    public String toString() {
        return "Pair(left=" + this.left + ", right=" + this.right + ")";
    }

    public static class PairBuilder {
        private Object left;
        private Object right;

        PairBuilder() {
        }

        public Pair.PairBuilder left(Object left) {
            this.left = left;
            return this;
        }

        public Pair.PairBuilder right(Object right) {
            this.right = right;
            return this;
        }

        public Pair build() {
            return new Pair(left, right);
        }

        public String toString() {
            return "Pair.PairBuilder(left=" + this.left + ", right=" + this.right + ")";
        }
    }
}

所以你可以清楚地使用@Value和@Builder

Answer 2

从版本1.16.10开始,当您同时使用它们时,构造函数不公开.

您可以添加@AllArgsConstructor来弥补这一点.