j1n*_*nrg 1 java iteration loops arraylist
我试图从a中删除重复的对象ArrayList并对某个字段的值求和.例如:
如果我有一个ArrayList对象"硬件":
{[Name: Ram, Quantity: 2],
[Name: Keyboard, Quantity: 3],
[Name: Mouse, Quantity: 5],
[Name: Keyboard, Quantity 5]}
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我想写一个能找到重复数并将数量相加的函数.在这种情况下,键盘是重复的,所以最终ArrayList应该是这样的:
{[Name: Ram, Quantity: 2],
[Name: Keyboard, Quantity: 8],
[Name: Mouse, Quantity: 5]}.
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我已经尝试过它,它似乎有时会起作用,但有时会错过元素.
List<Hardware> myList = new ArrayList<Hardware>();
myList.add(new Hardware("Ram", 2);
myList.add(new Hardware("Keyboard", 3);
myList.add(new Hardware("Mouse", 5);
myList.add(new Hardware("Keyboard", 5);
for(int i = 0; i < list.size(); i++){
Hardware current = list.get(i);
for(int j = 1; j < list.size(); j++){
Hardware compare = list.get(j);
if(current.getName().equals(compare.getName)){
current.setQuantity(current.getQuantity()
+ compare.getQuantity())
list.remove(compare);
}
}
}
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j如果你删除了这个项目,你不想增加; 它会让你跳过紧接着的项目.1,你想要启动它i+1,因为你不需要检查任何先前的元素.myList为list并且您缺少一些括号和分号试试这个:
List<Hardware> list = new ArrayList<Hardware>();
list.add(new Hardware("Ram", 2));
list.add(new Hardware("Keyboard", 3));
list.add(new Hardware("Mouse", 5));
list.add(new Hardware("Keyboard", 5));
list.add(new Hardware("Mouse", 1));
for (int i = 0; i < list.size(); i++) {
Hardware current = list.get(i);
for (int j = i + 1; j < list.size(); j++) {
Hardware compare = list.get(j);
if (current.getName().equals(compare.getName())) {
current.setQuantity(current.getQuantity() + compare.getQuantity());
list.remove(compare);
j--;
}
}
}
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您还应该查看此链接,以帮助您解决以下问题:
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