在Python单元测试中是否存在子列表的断言？

Question

对于Python 2.7:

list1 = [1, 2]

self.assertIn(1, list1)
self.assertIn(2, list1)

有没有办法让我更轻松？就像是:

self.assertIn((1,2), list1)  # I know this is wrong, just an example

Answer 1

尝试

self.assertTrue(all(x in list1 for x in [1,2]))

如果你可以使用pytest-django,你可以使用本机断言语句:

assert all(x in in list1 for x in [1,2])

Answer 2

我确定你已经弄明白但是你可以使用一个循环:

tested_list = [1, 2, 3]
checked_list = [1, 2]

# check that every number in checked_list is in tested_list:
for num in checked_list:
    self.assertIn(num, tested_list)

这对于缺少的特定数字失败,tested_list因此您可以立即知道问题所在.