Python和Shapefile：导入shapefile后坐标非常大

Question

我下载了波士顿的形状文件，并想使用下面的代码将其绘制出来。然而它给了我一个错误ValueError: lat_0 must be between -90.000000 and 90.000000 degrees

原来coords是有值的(33869.92130000144, 777617.2998000011, 330800.31099999696, 959741.1853)为什么这么大？

波士顿形状文件在此处获取

代码

# Import Boston shapefile
shapefilename = 'ZIPCODES_NT_POLY'
shp = fiona.open(shapefilename + '.shp')
coords = shp.bounds
shp.close()

w, h = coords[2] - coords[0], coords[3] - coords[1]
extra = 0.01

m = Basemap(
    projection='tmerc', ellps='WGS84',
    lon_0 = np.mean([coords[0], coords[2]]), 
    lat_0 = np.mean([coords[1], coords[3]]), 
    llcrnrlon = coords[0] - extra * w,
    llcrnrlat = coords[1] - extra * h,
    urcrnrlon = coords[2] + extra * w,
    urcrnrlat = coords[3] + extra * h,
    resolution = 'i', suppress_ticks = True)

错误

ValueError: lat_0 must be between -90.000000 and 90.000000 degrees

Answer 1

您需要从东距和北距的本机投影重新投影到另一个坐标参考系。如果您想要纬度和经度，通常是WGS84或EPSG:4326。以下是重新投影的方法：

import fiona
import pyproj
from functools import partial
from shapely.geometry import box
from shapely.ops import transform

shp = fiona.open('ZIPCODES_NT_POLY.shp', 'r')
p_in = pyproj.Proj(shp.crs)
bound_box = box(*shp.bounds)
shp.close()

p_out = pyproj.Proj({'init': 'EPSG:4326'})  # aka WGS84
project = partial(pyproj.transform, p_in, p_out)

bound_box_wgs84 = transform(project, bound_box)

print('native box: ' + str(bound_box))
print('WGS84 box: ' + str(bound_box_wgs84))

原生框：多边形（（330800.310999997 777617.2998000011、330800.310999997 959741.1853、33869.92130000144 959741.1853、33869.92130000144 777617.2998000011, 330800.310999997 777617.2998000011))

WGS84 框：多边形 ((-69.93980848410942 41.23787282321487，-69.899038698261 42.87724537285449，-73.53324195423785 42.8704709990465，-73。 48147096070339 41.2312695091688,-69.93980848410942 41.23787282321487))

不然Basemap需要的大部分参数都在shp.crs（看一下）。