处理UrlFetchApp.fetch()中的404错误

Question

我正在Google Spreadsheets中创建扩展程序,我正在尝试处理urlFetch()可能提供的404错误.现在它只是在电子表格的顶部显示一个弹出窗口,如下所示:

http://i.stack.imgur.com/fvCPC.png

这是我的代码:

function doTestAPICall() {
  var headers = {
    'Authorization': 'Basic ' + Utilities.base64Encode(user + "/token:" + token)
  };
  var url = "https://" + subdomain + ".domain.com/api/v2/users/me.json";
  var options = {
    'contentType': 'application/json',
    'method': 'get',
    'headers': headers
  };
  var response = UrlFetchApp.fetch(url, options);
  if(response.getResponseCode() == 200){
    var json = response.getContent();
    var data = JSON.parse(json);
    if(data.user.email != user){
      return false;
    } else {
      //User was correctly authenticated
      return true;
    } 
  }else{
    return false;
  }
}

但是,该函数永远不会到达response.getResponseCode(),因为它已经在UrlFetchApp.fetch函数上失败了.有关如何处理此问题的任何想法/建议？

谢谢!

---编辑---

根据Amit的建议,在UrlFetchApp选项中添加muteHttpExceptions解决了这个问题.

代码现在看起来像这样:

function doTestAPICall() {
  var headers = {
    'Authorization': 'Basic ' + Utilities.base64Encode(user + "/token:" + token)
  };
  var url = "https://" + subdomain + ".domain.com/api/v2/users/me.json";
  var options = {
    'contentType': 'application/json',
    'method': 'get',
    'headers': headers,
    'muteHttpExceptions': true
  };
  var response = UrlFetchApp.fetch(url, options);
  if(response.getResponseCode() == 200){
    var json = response.getContentText();
    var data = JSON.parse(json);
    if(data.user.email != user){
      return false;
    } else {
      //User was correctly authenticated
      return true;
    } 
  }else{
    return false;
  }
}

Answer 1

您可以在HTTP请求中将muteHttpExceptions设置为true以抑制这些错误.

function fetchPage() {
  var response = UrlFetchApp.fetch("http://ctrlq.org/404", {muteHttpExceptions: true});
  if (response.getResponseCode() == 404) {
    Logger.log("Web page not found");
  }
}