如何在MySQL中移动列值？

Question

我有这张桌子:

table1
+------+----------+-----------+----------+
|  id  | org1     | org2      | org3     |
+------+----------+-----------+----------+
|  1   | HR       | (NULL)    | Staff    |
+------+----------+-----------+----------+
|  2   | (NULL)   | IT        | Dev      |
+------+----------+-----------+----------+
|  3   | (NULL)   | (NULL)    | Finance  |
+------+----------+-----------+----------+

我想将所有值都移到左边,所以最终结果是:

table1
+------+----------+-----------+----------+
|  id  | org1     | org2      | org3     |
+------+----------+-----------+----------+
|  1   | HR       | Staff     | (NULL)   |
+------+----------+-----------+----------+
|  2   | IT       | Dev       | (NULL)   |
+------+----------+-----------+----------+
|  3   | Finance  | (NULL)    | (NULL)   |
+------+----------+-----------+----------+

这有什么优雅的方式吗？

Answer 1

更新：

根据cars10的答案，需要切换顺序COALESCE(org2,org3)并考虑所有 3 列的情况NOT NULL

SELECT id, o1, 
       CASE WHEN o2!=o1 THEN o2 END o2,
       CASE WHEN o3!=o2 THEN o3 END o3 
FROM
(
SELECT id
,COALESCE(org1,org2,org3) o1
,IF((org1 IS NOT NULL) AND (org2 IS NOT NULL) AND (org3 IS NOT NULL),
    org2,
    COALESCE(org3,org2)
) o2
,org3 o3
FROM table1
) t

添加 cars10 提到的案例：

DROP TABLE IF EXISTS table1;
CREATE TABLE `table1` (
  `id` INT(11) NOT NULL AUTO_INCREMENT,
  `org1` VARCHAR(255) DEFAULT NULL,
  `org2` VARCHAR(255) DEFAULT NULL,
  `org3` VARCHAR(255) DEFAULT NULL,  
  PRIMARY KEY (`id`)
);

INSERT INTO `table1` VALUES ('1', NULL, 'IT', 'DEV');
INSERT INTO `table1` VALUES ('2', 'HR',NULL,'Staff');
INSERT INTO `table1` VALUES ('3', 'ID','Building',NULL);
INSERT INTO `table1` VALUES ('4', 'Support','Business','1st line');

INSERT INTO `table1` VALUES ('5','Finance', NULL, NULL);
INSERT INTO `table1` VALUES ('6', NULL, 'Finance', NULL );
INSERT INTO `table1` VALUES ('7', NULL, NULL, 'Finance');
INSERT INTO `table1` VALUES ('8', NULL, NULL, NULL);

http://www.sqlfiddle.com/#!9/cd969/1

正如Thorsten Kettner提到的，没有优雅的方法可以做到这一点。我在上面找到了最短的工作解决方案。