我有一个如下所示的 CSV 文件:
patient_id, age_in_years, CENSUS_REGION, URBAN_RURAL_STATUS
11511, 7 Northeast, Urban,
9882613, 73, South, Urban,
32190339, 49, West, Urban,
32190339, 49, West, Urban,
32190339, 49, West, Urban,
32190339, 49, West, Urban,
.....
Run Code Online (Sandbox Code Playgroud)
现在我的代码是这样的:
df = pd.read_csv(filename, index_col = 0)
Run Code Online (Sandbox Code Playgroud)
这给出了以下输出:
patient_id age_in_years CENSUS_REGION URBAN_RURAL_STATUS YEAR MONTH
11511 7 Northeast Urban 2011 6
9882613 73 South Urban 2011 7
32190339 49 West Urban 2011 8
32190339 49 West Urban 2011 8
32190339 49 West Urban 2011 8
32190339 49 West Urban 2011 8
32190339 49 West Urban 2011 8
32190339 49 West Urban 2011 8
...
Run Code Online (Sandbox Code Playgroud)
我可以通过以下方式获取特定的列,例如 CENSUS_REGION
print(df['CENSUS_REGION'])
Run Code Online (Sandbox Code Playgroud)
但我想获取 CSV 中的特定单元格。任何人都可以帮我解决这个问题吗?
After getting the column, you can subscript using the index to get the specific value for that cell.
Example , in your case, your first column seems to be patient_id , so that is the index, you can index using that.
Example -
print(df['CENSUS_REGION'][11511])
Run Code Online (Sandbox Code Playgroud)
The above would get the data of CENSUS_REGION column for the patient with id - 11511 .
Example/Demo -
In [32]: df
Out[32]:
age_in_years CENSUS_REGION URBAN_RURAL_STATUS
patient_id
11511 7 Northeast Urban
9882613 73 South Urban
32190339 49 West Urban
32190339 49 West Urban
32190339 49 West Urban
32190339 49 West Urban
In [33]: df[' CENSUS_REGION']
Out[33]:
patient_id
11511 Northeast
9882613 South
32190339 West
32190339 West
32190339 West
32190339 West
Name: CENSUS_REGION, dtype: object
In [34]: df[' CENSUS_REGION'][11511]
Out[34]: ' Northeast'
Run Code Online (Sandbox Code Playgroud)
Please note, I had to use lots of spaces, since the csv was messed up, but ' CENSUS_REGION' is just the column name.
| 归档时间: |
|
| 查看次数: |
11363 次 |
| 最近记录: |