Bid*_*dou 13 .net c# mapping automapper
我有两个非常简单的对象:
public class CategoryDto
{
public string Id { get; set; }
public string MyValueProperty { get; set; }
}
public class Category
{
public string Id { get; set; }
[MapTo("MyValueProperty")]
public string Key { get; set; }
}
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使用AutoMapper Category将a 映射到a CategoryDto时,我想要以下行为:
除了具有该MapTo属性的属性之外,应该像往常一样映射属性.在这种情况下,我必须读取Attribute的值来查找target属性.source属性的值用于在destination属性中查找要注入的值(借助字典).一个例子总是好于1000字......
例:
Dictionary<string, string> keys =
new Dictionary<string, string> { { "MyKey", "MyValue" } };
Category category = new Category();
category.Id = "3";
category.Key = "MyKey";
CategoryDto result = Map<Category, CategoryDto>(category);
result.Id // Expected : "3"
result.MyValueProperty // Expected : "MyValue"
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该Key属性被映射到MyValueProperty(通过MapTo属性),并且赋值是"MyValue",因为源属性值是"MyKey",它被映射(通过字典)到"MyValue".
这可以使用AutoMapper吗?我当然需要一个适用于每个对象的解决方案,而不仅仅是Category/CategoryDto.
Bid*_*dou 10
我终于(经过这么多小时!!!!)找到了解决方案.我与社区分享这个; 希望它会帮助别人......
编辑:注意它现在更简单(AutoMapper 5.0+),你可以像我在这篇文章中回答的那样:如何使AutoMapper根据MaxLength属性截断字符串?
public static class Extensions
{
public static IMappingExpression<TSource, TDestination> MapTo<TSource, TDestination>(this IMappingExpression<TSource, TDestination> expression)
{
Type sourceType = typeof(TSource);
Type destinationType = typeof(TDestination);
TypeMap existingMaps = Mapper.GetAllTypeMaps().First(b => b.SourceType == sourceType && b.DestinationType == destinationType);
string[] missingMappings = existingMaps.GetUnmappedPropertyNames();
if (missingMappings.Any())
{
PropertyInfo[] sourceProperties = sourceType.GetProperties();
foreach (string property in missingMappings)
{
foreach (PropertyInfo propertyInfo in sourceProperties)
{
MapToAttribute attr = propertyInfo.GetCustomAttribute<MapToAttribute>();
if (attr != null && attr.Name == property)
{
expression.ForMember(property, opt => opt.ResolveUsing(new MyValueResolve(propertyInfo)));
}
}
}
}
return expression;
}
}
public class MyValueResolve : IValueResolver
{
private readonly PropertyInfo pInfo = null;
public MyValueResolve(PropertyInfo pInfo)
{
this.pInfo = pInfo;
}
public ResolutionResult Resolve(ResolutionResult source)
{
string key = pInfo.GetValue(source.Value) as string;
string value = dictonary[key];
return source.New(value);
}
}
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