在PHP中提取缩略图

dan*_*dan 18 html javascript php jquery

我有一个滑块(flexslider),我用它来显示以下jsfiddle中显示的形式的图像...我优化了滑块,以便它动态地提取图像(使用数字命名,例如:12364,50046)某个目录基于其名称.

JSFIDDLE:https://jsfiddle.net/atkumqpk/1/

提取图像的代码:

<?php
function get_slide_images($folder, $images_per_slide = 10, $starts_with = '') {

    $slide_images = false;

    // valid extensions
    $extensions = array(
        "jpg",
        "gif",
        "jpeg",
        "svg",
        "png",
        "bmp",
        "JPG"
    );

    // Implode the extensions array into a string:
    $extensions = implode(',', $extensions);

    if (file_exists($folder)) {
        // Get all the files with a valid extension in $folder:
        // (optionally filtered by $starts_with)
        foreach (glob($folder.'/{'.$starts_with.'}*.{'.$extensions.'}', GLOB_BRACE) as $filename) {
            $slide_images[$filename] = "<img src='{$filename}' alt='{$filename}' />";
        }

        if (!empty($slide_images)) {
            ksort($slide_images);
            $slide_images = array_chunk($slide_images, $images_per_slide);
        }

    }

    return $slide_images;
}
?>

<div id="logo" class="logo" ><img src="logo.png"/></div>
<p class="custom-class"><a href="">Go to the main website</a></p>

<div id="menu" class="menu">
    <ul class="headlines">
         <li id="item1">
        <button>aaaaaaaa</button>
        </li>
        <li id="item2">
            <button>bbbbbbb</button>
        </li>
        <li id="item3">
            <button>ccccccc</button>
        </li>
        <li id="item4">
            <button>dddddddd</button>
        </li>
        <li id="item5">
            <button>eeeeeee eee.</button>
        </li>
        <li id="item6">
            <button>ffffff</button>
        </li>
        <li id="item7">
            <button>ggggggg</button>
        </li>

    </ul>
</div>


<div id="container">
    <div id="first" class="inner-container">
        <div id="item11" class="item">
            <a name="item11"></a>
            <div class="flexslider">
                <ul class="slides">
<?php
$slider_kvp = get_slide_images("images", 10, "1");

/**
* Here we are going to generate the SLIDES
*/
if ($slider_kvp) {

    $slider_list_html = array();

    foreach($slider_kvp as $slider_key => $slide_images) {
        $html_LI_list = "";
        $html_LI_list = "<li>";

        // Go through each image ...
        foreach($slide_images as $image_key => $image_value) {
            $html_LI_list .= $image_value;
        }

        $html_LI_list .= "</li>";
        $slider_list_html[$slider_key] = $html_LI_list;
    }

    // OUR SLIDES!
    $rendered_slider_list_html = implode(' ', $slider_list_html);
    echo "<ul class='slides'>{$rendered_slider_list_html}</ul>";
}
?>

                </ul>
            </div>
        </div>
    </div>
</div>
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现在的问题是,当我有原始滑块(优化之前)时,我将它连接到"fancybox"以显示缩略图和隐藏图像.但是现在我不知道如何将它连接到使用php提取的图像.

Fancybox的代码.JSFIDDLE:http://jsfiddle.net/ny9ytae5/2/

案例:在目录图像内部(我正在从中提取图像)我有以数字命名的图像(例如:54236),并且对于每个图像,具有相同名称的等效文件夹(例如:对于图像54236,存在文件夹54236).文件夹54236的内容是需要连接到图像54236的缩略图.

我被stackoverflow成员"JFK"通知我可以这样做:" $slide_images[$filename] = "<img src='{$filename}' alt='{$filename}' />";可以改成这个$slide_images[$filename] = "<a class='fancybox' data-fancybox-group='thumb1' href='{$filename}'><img src='{$filename}' alt='{$filename}' /></a>";...唯一的问题是你将使用与缩略图相同的图像,这将增加你的页面加载的开销."

建议使用本教程:http://www.picssel.com/create-a-filtered-image-gallery-with-jquery-and-fancybox-part-2-create-image-thumbnails-with-php/

但是我没能成功.有什么帮助吗?

oli*_*ool 9

在"JFK"建议中,您应该将src属性指向缩略图图像(并将href属性设置为大尺寸图像)

就像是

$slide_images[$filename] = "<a class='fancybox' data-fancybox-group='thumb1' href='{$filename}'><img src='{$filename}/thumbnail.jpg' alt='{$filename}' /></a>";
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因此,缩略图将立即加载,但只有在需要时才会加载大图像.