拆分/标记/扫描一个知道引号的字符串

Question

Java中是否存在用于拆分字符串的默认/简单方法,但是要使用引号或其他符号？

例如,给定此文本:

There's "a man" that live next door 'in my neighborhood', "and he gets me down..."

获得:

There's
a man
that
live
next
door
in my neighborhood
and he gets me down

Answer 1

这样的东西适用于您的输入:

    String text = "There's \"a man\" that live next door "
        + "'in my neighborhood', \"and he gets me down...\"";

    Scanner sc = new Scanner(text);
    Pattern pattern = Pattern.compile(
        "\"[^\"]*\"" +
        "|'[^']*'" +
        "|[A-Za-z']+"
    );
    String token;
    while ((token = sc.findInLine(pattern)) != null) {
        System.out.println("[" + token + "]");
    }

以上打印(如ideone.com上所示):

[There's]
["a man"]
[that]
[live]
[next]
[door]
['in my neighborhood']
["and he gets me down..."]

它使用Scanner.findInLine,正则表达式模式是以下之一:

"[^"]*"      # double quoted token
'[^']*'      # single quoted token
[A-Za-z']+   # everything else

毫无疑问,这并不总是100%有效; 引号可以嵌套等的情况将是棘手的.

参考

• regular-expressions.info/Character类