Okh*_*bay 6 switch-statement ios swift
我有这个代码
import UIKit
enum menuSituation{
case menuIsOpened
case menuIsClosed
}
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
var currentSituation = menuSituation.menuIsClosed
switch(currentSituation){ //Here is the warning
case .menuIsOpened:
println("Menu is opened")
break
case .menuIsClosed:
println("Menu is closed")
break
}
}
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在我开始定义switch语句的行中,它给出了警告:
切换条件评估为常量
我怎么能摆脱这个警告?
All*_*ian 10
好吧,它基本上意味着交换机将始终评估为menuIsClosed.你可能意味着这样的事情:
var currentSituation = aSituation // That would be a menuSituation (known at runtime)
// Also note that 'break' is not needed in (non-empty) match cases
switch currentSituation {
case .menuIsOpened:
println("Menu is opened")
case .menuIsClosed:
println("Menu is closed")
}
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