matplotlib.pyplot来自颜色字典的散点图

Question

我正在尝试用我的D_id_color字典为我的散点图创建一个图例.如何根据这些值和实际颜色创建图例？

#!/usr/bin/python
import matplotlib.pyplot as plt
from matplotlib import colors
D_id_color = {'A': u'orchid', 'B': u'darkcyan', 'C': u'grey', 'D': u'dodgerblue', 'E': u'turquoise', 'F': u'darkviolet'}
x_coordinates = [1,2,3,4,5]
y_coordinates = [3,3,3,3,3]
size_map = [50,100,200,400,800]
color_map = [color for color in D_id_color.values()[:len(x_coordinates)]]

plt.scatter(x_coordinates,y_coordinates, s = size_map, c = color_map)
plt.show()

我希望图例看起来像这样,但它不是颜色名称,而是具有实际颜色.

A orchid
C grey
B darkcyan
E turquoise
D dodgerblue
F darkviolet

Answer 1

实现这一目标的一种方法:

D_id_color = {'A': u'orchid', 'B': u'darkcyan', 'C': u'grey', 'D': u'dodgerblue', 'E': u'turquoise', 'F': u'darkviolet'}
x_coordinates = [1,2,3,4,5,6] # Added missing datapoint
y_coordinates = [3,3,3,3,3,3] # Added missing datapoint
size_map = [50,100,200,400,800,1200] # Added missing datapoint
color_map = [color for color in D_id_color.values()[:len(x_coordinates)]]
plt.scatter(x_coordinates,y_coordinates, s = size_map, c = color_map)

# The following two lines generate custom fake lines that will be used as legend entries:
markers = [plt.Line2D([0,0],[0,0],color=color, marker='o', linestyle='') for color in D_id_color.values()]
plt.legend(markers, D_id_color.keys(), numpoints=1)

plt.show()

这将产生: