我有一个分页,我想实现并限制为5页数,
见下文:
例子:
PREVIOUS 1 2 3 4 5 NEXT
PREVIOUS 20 21 22 23 ... 39 NEXT
PREVIOUS 59 ... 81 82 83 84 NEXT
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只需要显示五个页码.
我应该改变和修改哪部分代码?
我在组合方面遇到了麻烦.
<?php
/* Setup page vars for display. */
if ($page == 0) $page = 1; //if no page var is given, default to 1.
$prev = $page - 1; //previous page is page - 1
$next = $page + 1; //next page is page + 1
$lastpage = ceil($total_pages/$limit); //lastpage is = total pages / items per page, rounded up.
$lpm1 = $lastpage - 1; //last page minus 1
/*
Now we apply our rules and draw the pagination object.
We're actually saving the code to a variable in case we want to draw it more than once.
*/
$pagination = "";
if($lastpage > 1)
{
$pagination .= "<div class=\"pagination\">";
//previous buttons
if ($page > 1)
$pagination.= "<a class='buttons' href=\"$targetpage?page=$prev\">previous</a>";
else
$pagination.= "<a class='disabled'><buttons disabled>previous</buttons></a>";
//pages
if ($lastpage < 7 + ($adjacents * 2)) //not enough pages to bother breaking it up
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<a class='current'><buttons style='background-color:#CEF6F5'>$counter</buttons></a>";
else
$pagination.= "<a class='buttons' href=\"$targetpage?page=$counter\">$counter</a>";
}
}
elseif($lastpage > 5 + ($adjacents * 2)) //enough pages to hide some
{
//close to beginning; only hide later pages
if($page < 1 + ($adjacents * 2))
{
for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
{
if ($counter == $page)
$pagination.= "<a class='current'><buttons style='background-color:#CEF6F5'>$counter</buttons></a>";
else
$pagination.= "<a class='buttons' href=\"$targetpage?page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a class='buttons' href=\"$targetpage?page=$lpm1\">$lpm1</a>";
$pagination.= "<a class='buttons' href=\"$targetpage?page=$lastpage\">$lastpage</a>";
}
//in middle; hide some front and some back
elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
{
$pagination.= "<a class='buttons' href=\"$targetpage?page=1\"> 1 </a>";
$pagination.= "<a class='buttons' href=\"$targetpage?page=2\"> 2 </a>";
$pagination.= "...";
for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
{
if ($counter == $page)
$pagination.= "<a class='current'><buttons style='background-color:#CEF6F5'>$counter</buttons></a>";
else
$pagination.= "<a class='buttons' href=\"$targetpage?page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a class='buttons' href=\"$targetpage?page=$lpm1\">$lpm1</a>";
$pagination.= "<a class='buttons' href=\"$targetpage?page=$lastpage\">$lastpage</a>";
}
//close to end; only hide early pages
else
{
$pagination.= "<a href=\"$targetpage?page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?page=2\">2</a>";
$pagination.= "...";
for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<a class='current'><buttons style='background-color:#CEF6F5'>$counter</buttons></a>";
else
$pagination.= "<a class='buttons' href=\"$targetpage?page=$counter\">$counter</a>";
}
}
}
//next buttons
if ($page < $counter - 1)
$pagination.= "<a class='buttons' href=\"$targetpage?page=$next\">next</a>";
else
$pagination.= "<a class='buttons'>next</a>";
$pagination.= "</div>\n";
}
?>
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我有问题跟踪显示页码的限制.
这对我有用。您必须将当前页码和总页数传递给该函数。
function pageRange(page,pageCount){
var start = page-2,
end = page+2;
if(end>pageCount){
start-=(end-pageCount);
end=pageCount;
}
if(start<=0){
end+=((start-1)*(-1));
start=1;
}
end = end>pageCount?pageCount:end;
return {start:start, end:end};
}
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编辑:看看我制作的这个小提琴https://jsfiddle.net/qsLp6ajL/2/
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