Mis*_*ppi 2 concatenation swift
我希望不同类型之间的连接在Swift中是直截了当的,但显然不是.这是什么解决方法?
var boy = "Bart Simpson"
var age = 7
print(boy + " is " + age)
Run Code Online (Sandbox Code Playgroud)
vad*_*ian 13
非常容易,包裹所有可打印的对象 \( )
let boy = "Bart Simpson"
let age = 7
println("\(boy) is \(age)")
Run Code Online (Sandbox Code Playgroud)
let boy = "Bart Simpson"
let age = 7
let sentence = String(format:"%@ is %d", boy, age)
println(sentence) // "Bart Simpson is 7"
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
5398 次 |
| 最近记录: |