use*_*315 5 python scrapy web-scraping
我已经使用pip安装了scrapy并尝试了scrapy文档中的示例.
我收到了错误 cannot import name xmlrpc_client
在查看stachoverflow问题后, 我已经使用它修复了它
sudo pip uninstall scrapy
sudo pip install scrapy==0.24.2
Run Code Online (Sandbox Code Playgroud)
但现在它告诉我 exceptions.AttributeError: 'HtmlResponse' object has no attribute 'urljoin'
这是我的代码:
import scrapy
class StackOverflowSpider(scrapy.Spider):
name = 'stackoverflow'
start_urls = ['https://stackoverflow.com/questions?sort=votes']
def parse(self, response):
for href in response.css('.question-summary h3 a::attr(href)'):
full_url = response.urljoin(href.extract())
yield scrapy.Request(full_url, callback=self.parse_question)
def parse_question(self, response):
yield {
'title': response.css('h1 a::text').extract()[0],
'votes': response.css('.question .vote-count-post::text').extract()[0],
'body': response.css('.question .post-text').extract()[0],
'tags': response.css('.question .post-tag::text').extract(),
'link': response.url,
}
Run Code Online (Sandbox Code Playgroud)
任何人都可以帮助我!
在Scrapy> = 0.24.2中,HtmlResponse类还没有urljoin()方法.urlparse.urljoin()直接使用:
full_url = urlparse.urljoin(response.url, href.extract())
Run Code Online (Sandbox Code Playgroud)
别忘了导入它:
import urlparse
Run Code Online (Sandbox Code Playgroud)
请注意,urljoin()在Scrapy 1.0中添加了别名/帮助程序,这是相关问题:
这里是它实际上是什么:
from six.moves.urllib.parse import urljoin
def urljoin(self, url):
"""Join this Response's url with a possible relative url to form an
absolute interpretation of the latter."""
return urljoin(self.url, url)
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
2404 次 |
| 最近记录: |