我在 PHPUnit 手册中读到,在下面的例子中,方法调用doSomething('a','b','c')将返回d,方法调用doSomething('e','f','g')将返回h.
<?php
require_once 'SomeClass.php';
class StubTest extends PHPUnit_Framework_TestCase
{
public function testReturnValueMapStub()
{
// Create a stub for the SomeClass class.
$stub = $this->getMockBuilder('SomeClass')
->getMock();
// Create a map of arguments to return values.
$map = array(
array('a', 'b', 'c', 'd'),
array('e', 'f', 'g', 'h')
);
// Configure the stub.
$stub->method('doSomething')
->will($this->returnValueMap($map));
// $stub->doSomething() returns different values depending on
// the provided arguments.
$this->assertEquals('d', $stub->doSomething('a', 'b', 'c'));
$this->assertEquals('h', $stub->doSomething('e', 'f', 'g'));
}
}
?>
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是否还有一种方法可以定义这样的返回值映射,但是当特定输入参数没有特定返回值时使用默认返回值?
小智 5
您可以使用 returnCallback 而不是 returnValueMap,并重现值映射正在做什么:
<?php
require_once 'SomeClass.php';
class StubTest extends PHPUnit_Framework_TestCase
{
public function testReturnValueMapStub()
{
// Create a stub for the SomeClass class.
$stub = $this->getMockBuilder( 'SomeClass' )
->getMock();
// Create a map of arguments to return values.
$valueMap = array(
array( 'a', 'b', 'c', 'd' ),
array( 'e', 'f', 'g', 'h' )
);
$default = 'l';
// Configure the stub.
$stub->method( 'doSomething' )
->will( $this->returnCallback( function () use ( $valueMap, $default )
{
$arguments = func_get_args();
$parameterCount = count( $arguments );
foreach( $valueMap as $map )
{
if( !is_array( $map ) || $parameterCount != count( $map ) - 1 )
{
continue;
}
$return = array_pop( $map );
if( $arguments === $map )
{
return $return;
}
}
return $default;
} ) );
// $stub->doSomething() returns different values depending on
// the provided arguments.
$this->assertEquals( 'd', $stub->doSomething( 'a', 'b', 'c' ) );
$this->assertEquals( 'h', $stub->doSomething( 'e', 'f', 'g' ) );
$this->assertEquals( 'l', $stub->doSomething( 'i', 'j', 'k' ) );
$this->assertEquals( 'l', $stub->doSomething( 'any', 'arguments', 'at', 'all' ) );
}
}
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