同时关闭多个视图控制器

Question

我正在使用SpriteKit制作游戏.我有3个viewControllers:选择level vc,game vc和win vc.游戏结束后,我想显示win vc,然后如果我按下win vc上的OK按钮,我想解雇win vc和游戏vc(从堆栈中弹出两个视图控制器).但我不知道怎么做,因为如果我打电话

self.dismissViewControllerAnimated(true, completion: {})    

win vc(堆栈顶部)被解雇,所以我不知道在哪里再次调用它来解雇游戏vc.有没有办法在不使用导航控制器的情况下解决这个问题？

这是第一个VC :(请注意以下以"//"开头的评论)

class SelectLevelViewController: UIViewController { // I implemented a UIButton on its storyboard, and its segue shows GameViewController
    override func viewDidLoad() {
        super.viewDidLoad()
    }
}

这是第二个VC:

class GameViewController: UIViewController, UIPopoverPresentationControllerDelegate {
    var scene: GameScene!
    var stage: Stage!

    var startTime = NSTimeInterval()
    var timer = NSTimer()
    var seconds: Double = 0
    var timeStopped = false

    var score = 0

    @IBOutlet weak var targetLabel: UILabel!
    @IBOutlet var displayTimeLabel: UILabel!
    @IBOutlet weak var scoreLabel: UILabel!
    @IBOutlet weak var gameOverPanel: UIImageView!
    @IBOutlet weak var shuffleButton: UIButton!
    @IBOutlet weak var msNum: UILabel!

    var mapNum = Int()
    var stageNum = Int()

    var tapGestureRecognizer: UITapGestureRecognizer!

    override func viewDidLoad() {
        super.viewDidLoad()

        let skView = view as! SKView
        skView.multipleTouchEnabled = false

        scene = GameScene(size: skView.bounds.size)
        scene.scaleMode = .AspectFill
        msNum.text = "\(mapNum) - \(stageNum)"

        stage = Stage(filename: "Map_0_Stage_1")
        scene.stage = stage
        scene.addTiles()
        scene.swipeHandler = handleSwipe

        gameOverPanel.hidden = true
        shuffleButton.hidden = true

        skView.presentScene(scene)

        Sound.backgroundMusic.play()

        beginGame()
    }

    func beginGame() {
        displayTimeLabel.text = String(format: "%ld", stage.maximumTime)
        score = 0
        updateLabels()

        stage.resetComboMultiplier()

        scene.animateBeginGame() {
            self.shuffleButton.hidden = false
        }

        shuffle()

        startTiming()
    }

    func showWin() {
        gameOverPanel.hidden = false
        scene.userInteractionEnabled = false
        shuffleButton.hidden = true

        scene.animateGameOver() {
            self.tapGestureRecognizer = UITapGestureRecognizer(target: self, action: "hideWin")
            self.view.addGestureRecognizer(self.tapGestureRecognizer)
        }
    }

    func hideWin() {
        view.removeGestureRecognizer(tapGestureRecognizer)
        tapGestureRecognizer = nil

        gameOverPanel.hidden = true
        scene.userInteractionEnabled = true

        self.performSegueWithIdentifier("win", sender: self) // this segue shows WinVC but idk where to dismiss this GameVC after WinVC gets dismissed...
    }

    func shuffle() {...}
    func startTiming() {...}
}

这是第三个VC:

class WinVC: UIViewController {

    @IBOutlet weak var awardResult: UILabel!

    @IBAction func dismissVC(sender: UIButton) {
        self.dismissViewControllerAnimated(true, completion: {}) // dismissing WinVC here when this button is clicked
    }

    override func viewDidLoad() {
        super.viewDidLoad()
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
    }

}

Answer 1

@Ken Toh的评论是在这种情况下对我有用的 - 从视图控制器调用你想要在其他一切被解雇后显示的消除.

如果你有3个呈现视图控制器"栈" A,B和C,其中,C是在上面,然后调用A.dismiss(animated: true, completion: nil)将同时解雇B和C.

如果您没有对堆栈根目录的引用,则可以链接几个访问权限presentingViewController以获取它.像这样的东西:

self.presentingViewController?.presentingViewController?.dismiss(animated: true, completion: nil)

Answer 2

您可以在完成块中关闭WinVC的呈现控制器(GameViewController):

let presentingViewController = self.presentingViewController
self.dismissViewControllerAnimated(false, completion: {
  presentingViewController?.dismissViewControllerAnimated(true, completion: {})
})

或者,您可以联系到根视图控制器并调用dismissViewControllerAnimated,这将在单个动画中关闭两个模态视图控制器:

self.presentingViewController?.presentingViewController?.dismissViewControllerAnimated(true, completion: {})

Answer 3

Swift 5（可能还有 4、3 等）

presentingViewController?.presentingViewController?不是很优雅，在某些情况下不起作用。相反，使用segues.

比方说，我们有ViewControllerA，ViewControllerB和ViewControllerC。我们在ViewControllerC（我们通过ViewControllerA->到达这里ViewControllerB，所以如果我们这样做，dismiss我们将返回到ViewControllerB）。我们想从ViewControllerC直接跳回到ViewControllerA。

在ViewControllerA您的 ViewController 类中添加以下操作：

@IBAction func unwindToViewControllerA(segue: UIStoryboardSegue) {}

是的，这一行在你想要返回的 ViewController 的 ViewController 中！

现在，您需要从ViewControllerC的故事板 ( StoryboardC)创建退出转场。继续并打开StoryboardC并选择故事板。按住 CTRL 并拖动退出，如下所示：

您将获得一个 segue 列表供您选择，包括我们刚刚创建的一个：

你现在应该有一个 segue，点击它：

进入检查器并设置一个唯一的 id：

在ViewControllerC您想要关闭并返回的点ViewControllerA，执行以下操作（使用我们之前在检查器中设置的 id）：

self.performSegue(withIdentifier: "yourIdHere", sender: self)

Answer 4

你应该可以打电话:

self.presentingViewController.dismissViewControllerAnimated(true, completion: {});

(您可能需要添加?或在!某处 - 我不是一个快速的开发人员)

Answer 5

有一种特殊的展开策略，旨在将视图堆栈回滚到某些视图控制器。请在这里查看我的答案：如何在Swift iOS中关闭2 View Controller？

Answer 6

在我的应用程序中尝试接受的答案时，我遇到了一些动画问题。先前呈现的视图将在屏幕上闪烁或尝试动画。这是我的解决方案：

     if let first = presentingViewController,
        let second = first.presentingViewController,
            let third = second.presentingViewController {
                second.view.isHidden = true
                first.view.isHidden = true
                    third.dismiss(animated: true)

     }