在C＃cmdlet中创建PowerShell PSObject

Question

C＃的新手，但在PowerShell中经验丰富。接管别人的代码。编写已编译的PowerShell模块，并尝试弄清楚如何基于返回的数据创建对象。现在，代码返回一个字符串：

ServerResponse<UCCSiteModel> requestModel = this.MakeRequest("/site/api/", "site", "GET", this.Credentials, queryString);
StringBuilder builder = new StringBuilder();

if (requestModel != null && requestModel.Response != null)
{
    builder.AppendLine("SiteID: " + requestModel.Response.SiteID);
    builder.AppendLine("Identity: " + requestModel.Response.SiteName);
    builder.AppendLine("Site Code: " + requestModel.Response.SiteCode);
    builder.AppendLine("Contact Name: " + requestModel.Response.ContactName);
    builder.AppendLine("Contact Number: " + requestModel.Response.ContactNumber);
    builder.AppendLine("Contact Email Address: " + requestModel.Response.ContactEmailAddress);
    builder.AppendLine("Address: " + requestModel.Response.Address);
    builder.AppendLine("City: " + requestModel.Response.City);
    builder.AppendLine("State: " + requestModel.Response.State);
    builder.AppendLine("Post Code: " + requestModel.Response.PostCode);
    builder.AppendLine("Time Zone: " + requestModel.Response.Timezone);
    builder.AppendLine("Longitude: " + requestModel.Response.longitude);
    builder.AppendLine("Latitude: " + requestModel.Response.latitude);                    
    this.WriteResponse(requestModel, builder.ToString());
}

如何创建从中requestModel.Response发送回PowerShell而不是字符串的对象？在编写PowerShell时，通常会使用New-Object PsObject，然后使用Add-Member。不知道如何在C＃中执行此操作，或者不确定它的调用方式（以便可以搜索）。任何人？

Answer 1

您可以Add-Member通过调用您Add()的Members属性来反映其行为PSObject（为了方便在PowerShell中访问，我将属性名称更改为CamelCase）：

if (requestModel != null && requestModel.Response != null)
{
    PSObject responseObject = new PSObject();

    responseObject.Members.Add(new PSNoteProperty("SiteID", requestModel.Response.SiteID));
    responseObject.Members.Add(new PSNoteProperty("Identity", requestModel.Response.SiteName));
    // and so on etc... 
    responseObject.Members.Add(new PSNoteProperty("Latitude", requestModel.Response.latitude));

    this.WriteObject(responseObject);
}