uda*_*aya 10 html css php html-table
我在表格中填充数据库中的图像,如何将图像限制为每行三个?
<table border="0" align="center" height="25%" width="25%" >
<tr><td align="center" width="50px" bgcolor="#4b2d0e"><strong><font color="#FFFFFF">Friend List</font></strong></td></tr>
<? foreach($Selected as $row)
{
$value = $row['dPath'];
$imgp = base_url()."images"."/".$value;
?>
<tr><td bgcolor="#999999">
<strong ><?=$row['dFrindName'].'</br>';?></strong>
<? if($value!="") { ?>
<a class="Tab_Link" href="<? echo site_url();?>/friends/View_FProfile/<?=$row['dMember_Id']?>"><img src="<?=$imgp ?>" name="b1" width="90" height="80" border="0"/></a><br>
<? } else { ?>
<a class="Tab_Link" href="<? echo site_url();?>/friends/View_FProfile/<?=$row['dMember_Id']?>"><img src="../images/us.png" width="90px" height="80px"></a>
<? }?>
</td></tr>
<? }}?>
</table>
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这是我的桌子
<?php
$x=0;
foreach($Selected as $row){
if($x%3 == 0)
echo '<tr>';
$value = $row['dPath'];
$imgp = base_url()."images"."/".$value;
?>
<td style="background-color:#999999;">
<strong ><?=$row['dFrindName'].'</br>';?></strong>
<?php if($value!="") {?>
<a class="Tab_Link" href="<? echo site_url();?>/friends/View_FProfile/<?=$row['dMember_Id']?>"><img src="<?=$imgp ?>" name="b1" width="90" height="80" border="0"/></a><br>
<?php } else { ?>
<a class="Tab_Link" href="<? echo site_url();?>/friends/View_FProfile/<?=$row['dMember_Id']?>"><img src="../images/us.png" width="90px" height="80px"></a>
<?php }?>
</td>
<?php
if($x%3 == 0)
echo '</tr>';
x++;
}
if(($x-1)%3 != 0)
echo '</tr>'; //Prints out the last '<tr>' if one isn't printed.
?>
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您需要使用if带模数运算符.
在这里,我清理了无效的HTML,使用了CSS,并使用了更推荐的PHP编码风格.
请注意:您需要注意,如果$Selected包含用户输入的(或其他非HTML安全的)数据,则需要将输出包装在htmlspecialcharsXSS漏洞中或对XSS漏洞开放.
考虑到目前每行仅显示1个图像,想要"将图像限制为每行三个",这有点不清楚.如果我假设你想要每行显示3而不是1,那么你需要使用模数运算符并且只<tr>在每第三个元素之后打开一个新的,然后在正确的时间关闭它.像这样:
<style type="text/css">
a img { border: none; }
.friend-list { border: none; width: 25%; height: 25%; margin: 0 auto; }
.friend-list th { text-align: center; background-color: #4b2d0e; color: #fff; font-weight: bold; }
.friend-list td { background-color: #999999; }
</style>
<?php
$numCols = 3;
$colCount = -1;
?>
<table class="friend-list">
<tr>
<th colspan="<?php echo $numCols; ?>">Friend List</th>
</tr>
<?php
foreach($Selected as $row) {
$value = $row['dPath'];
$imgp = ($value) ? base_url().'images/'.$value : '../images/us.png';
if(++$colCount % $numCols == 0) {
echo '<tr>';
}
?>
<td>
<strong><?php echo $row['dFriendName']; ?></strong><br />
<a class="Tab_Link" href="<?php echo site_url(); ?>/friends/View_FProfile/<?php echo $row['dMember_Id']; ?>">
<img src="<?php echo $imgp; ?>" width="90" height="80" />
</a>
</td>
<?php
if(($colCount + 1) % $numCols == 0) {
echo '</tr>';
} elseif (($colCount + 1) == count($Selected)) {
// if 16 elements are to fit in 3 columns, print 2 empty <td>s before closing <tr>
$extraTDs = $numCols - (($colCount + 1) % $numCols);
for ($i = 0; $i < $extraTDs; $i++) {
echo '<td> </td>';
}
echo '</tr>';
}
}
?>
</table>
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应该为列和行有意义的情况保留表...更好的解决方案是使用浮动块元素而不是表格单元格.当你浮动一堆相似的块时,它们会自动换行,因此关键是使它们的父容器足够宽以容纳其中的3个.
你不需要用php做任何特殊的事情来创建新行,所以我只是显示html和css,让你编写php来实现它.
HTML:
<div id="replacesTable">
<div class="replacesTableCell">
<div class="name">Name</div>
<img src="http://stackoverflow.com/favicon.ico" />
</div>
<div class="replacesTableCell">
<div class="name">Name</div>
<img src="http://stackoverflow.com/favicon.ico" />
</div>
<div class="replacesTableCell">
<div class="name">Name</div>
<img src="http://stackoverflow.com/favicon.ico" />
</div>
<div class="replacesTableCell">
<div class="name">Name</div>
<img src="http://stackoverflow.com/favicon.ico" />
</div>
<div class="clear"> </div>
</div>
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CSS:
#replacesTable{
width: 300px;
}
div.replacesTableCell{
float:left;
width: 100px;
/* styles below are just to make it easier to see what's happening */
text-align:center;
font-size: 10px;
margin: 20px 0;
}
/* this just stretches the parent container #replacesTable around the entries*/
.clear{
clear:both;
height:1px;
overflow:hidden;
}
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