Bra*_*vis 3 sql google-bigquery
我对 BigQuery 和 SQL 有点陌生,所以我遇到的部分困难可能是我不知道如何描述我遇到的问题,以至于能够搜索答案,但我有看起来所以请温柔。
我想要做的是计算满足一组条件的唯一用户 ID 的总数,然后除以唯一用户 ID 的总数。
例如,要计算所有购买的唯一用户:
SELECT count(userId)
FROM (SELECT userId
FROM (FLATTEN([table1], user_attribute))
WHERE event_value > 0 and event_parameters.Name = "SKU"
GROUP BY userId ORDER BY userId)
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并计算唯一用户的总数
SELECT count(userId)
FROM (SELECT userId
FROM (FLATTEN([table1], user_attribute))
GROUP BY userId ORDER BY userId)
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我试图将查询写为
SELECT buyers/total
FROM (SELECT COUNT(userId) AS buyers
FROM (SELECT userId
FROM (FLATTEN([table1], user_attribute))
WHERE event_value > 0 and event_parameters.Name = "SKU"
GROUP BY userId ORDER BY userId),
COUNT(userId) as total
FROM (SELECT userId
FROM (FLATTEN([table1], user_attribute))
GROUP BY userId ORDER BY userId))
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但它不起作用。我知道我在做一些根本错误的事情,但我不确定它是什么。我将不胜感激任何帮助。
您可以像这样计算不同的用户:
SELECT
EXACT_COUNT_DISTINCT(userId) as buyers
FROM (FLATTEN([table1], user_attribute))
WHERE
event_value > 0
AND event_parameters.Name = "SKU"
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连接它们的一种方法是添加一个静态标量值并将其用于连接:
SELECT
buyers/total
FROM (
SELECT
EXACT_COUNT_DISTINCT(userId) AS buyers,
1 AS scalar,
FROM (FLATTEN([table1], user_attribute))
WHERE
event_value > 0
AND event_parameters.Name = "SKU") a
JOIN (
SELECT
COUNT(userId) AS total,
1 AS scalar,
FROM (FLATTEN([table1], user_attribute)) ) b
ON
a.scalar=b.scalar
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