Gop*_*opi 13 php arrays json repeat
所以我有这个JSON数组:
[0] => 238
[1] => 7
[2] => 86
[3] => 79
[4] => 55
[5] => 92
[6] => 55
[7] => 7
[8] => 254
[9] => 9
[10] => 75
[11] => 238
[12] => 89
[13] => 238
Run Code Online (Sandbox Code Playgroud)
我将在实际的JSON文件中拥有更多值.但通过观察,我可以看到238和55的重复次数超过任何其他数字.我想要做的是获取数组中前5个最重复的值并将它们存储在新的PHP数组中.
Joh*_*nde 33
$values = array_count_values($array);
arsort($values);
$popular = array_slice(array_keys($values), 0, 5, true);
Run Code Online (Sandbox Code Playgroud)
array_count_values() 获取每个项目在数组中出现的次数arsort() 按相反顺序对出现次数排序数组array_keys() 获取实际值,即结果中的数组键 array_count_values()array_slice() 给出了结果的前五个要素$array = [1,2,3,4,238, 7, 86, 79, 55, 92, 55, 7, 254, 9, 75, 238, 89, 238];
$values = array_count_values($array);
arsort($values);
$popular = array_slice(array_keys($values), 0, 5, true);
array (
0 => 238,
1 => 55,
2 => 7,
3 => 4,
4 => 3,
)
Run Code Online (Sandbox Code Playgroud)
关键是使用类似的东西array_count_values()计算每个值的出现次数.
<?php
$array = [238, 7, 86, 79, 55, 92, 55, 7, 254, 9, 75, 238, 89, 238];
// Get array of (value => count) pairs, sorted by descending count
$counts = array_count_values($array);
arsort($counts);
// array(238 => 3, 55 => 2, 7 => 2, 75 => 1, 89 => 1, 9 => 1, ...)
// An array with the first (top) 5 counts
$top_with_count = array_slice($counts, 0, 5, true);
// array(238 => 3, 55 => 2, 7 => 2, 75 => 1, 89 => 1)
// An array with just the values
$top = array_keys($top_with_count);
// array(238, 55, 7, 75, 89)
?>
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
7773 次 |
| 最近记录: |