Jav*_*oxs 6 python image python-imaging-library
我正在使用Python创建图像
myImage = Image.new('RGB', (250, 250), 'rgb(155,89,182)')
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这实际上创造了图像.但有没有办法创建一个图像,背景为我选择的颜色,但有渐变?我想选择蓝色作为我的颜色,然后,我希望边缘呈深蓝色,图像中心呈浅蓝色.这可能使用简单的PIL和Python吗?
先感谢您.
Leo*_*aum 12
代码取决于您希望渐变的外观.
您可以将其设为矩形渐变,如下所示:

或者你可以把它变成这样的圆形渐变:

这将是圆形渐变的代码:
import Image
import math
imgsize = (250, 250) #The size of the image
image = Image.new('RGB', imgsize) #Create the image
innerColor = [80, 80, 255] #Color at the center
outerColor = [0, 0, 80] #Color at the corners
for y in range(imgsize[1]):
for x in range(imgsize[0]):
#Find the distance to the center
distanceToCenter = math.sqrt((x - imgsize[0]/2) ** 2 + (y - imgsize[1]/2) ** 2)
#Make it on a scale from 0 to 1
distanceToCenter = float(distanceToCenter) / (math.sqrt(2) * imgsize[0]/2)
#Calculate r, g, and b values
r = outerColor[0] * distanceToCenter + innerColor[0] * (1 - distanceToCenter)
g = outerColor[1] * distanceToCenter + innerColor[1] * (1 - distanceToCenter)
b = outerColor[2] * distanceToCenter + innerColor[2] * (1 - distanceToCenter)
#Place the pixel
image.putpixel((x, y), (int(r), int(g), int(b)))
image.save('circlegradient.jpg')
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对于每个像素,它将红色,绿色和蓝色值设置在介于两者之间的某个位置innerColor,outerColor具体取决于从像素到中心的距离.
这将是矩形渐变的代码:
import Image
imgsize = (250, 250) #The size of the image
image = Image.new('RGB', imgsize) #Create the image
innerColor = [80, 80, 255] #Color at the center
outerColor = [0, 0, 80] #Color at the edge
for y in range(imgsize[1]):
for x in range(imgsize[0]):
#Find the distance to the closest edge
distanceToEdge = min(abs(x - imgsize[0]), x, abs(y - imgsize[1]), y)
#Make it on a scale from 0 to 1
distanceToEdge = float(distanceToEdge) / (imgsize[0]/2)
#Calculate r, g, and b values
r = innerColor[0] * distanceToEdge + outerColor[0] * (1 - distanceToEdge)
g = innerColor[1] * distanceToEdge + outerColor[1] * (1 - distanceToEdge)
b = innerColor[2] * distanceToEdge + outerColor[2] * (1 - distanceToEdge)
#Place the pixel
image.putpixel((x, y), (int(r), int(g), int(b)))
image.save('rectgradient.jpg')
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这种方法的工作方式相同,只是它测量到最近边缘的距离,而不是中心.