SQL Server:将sp_MSforeachdb转换为单个结果集

Question

我将进行存档以获取一个查询,该查询从所有数据库中提取一些数据并返回单个结果集.

现在我有以下内容:

DECLARE @command varchar(4000)
SELECT @command = '
USE [?] 
SELECT 
    database_name = DB_NAME(database_id)
    , log_size_mb = CAST(SUM(CASE WHEN type_desc = "LOG" THEN size END) * 8. / 1024 AS DECIMAL(8,2))
    , row_size_mb = CAST(SUM(CASE WHEN type_desc = "ROWS" THEN size END) * 8. / 1024 AS DECIMAL(8,2))
    , total_size_mb = CAST(SUM(size) * 8. / 1024 AS DECIMAL(8,2))
    , Kostenstelle = (select value from sys.extended_properties WHERE name =     "Kostenstelle")
FROM sys.master_files WITH(NOWAIT)
WHERE database_id = DB_ID()
GROUP BY database_id
'
EXEC sp_MSforeachdb @command

上面的代码将返回多个结果集.

结果应如下所示:

|database_name|log_size_mb|row_size_mb|Kostenstelle|
+-------------+-----------+-----------+------------+
|demoA        |         12|         10|        xxxx|
|demoB        |         52|         12|        xxxx|

Answer 1

得到了同事的回复 - 1000谢谢

DECLARE @command varchar(4000)
SELECT @command = '
USE [?] 
SELECT 
database_name = CAST(DB_NAME(database_id) AS VARCHAR(50))
, log_size_mb = CAST(SUM(CASE WHEN type_desc = "LOG" THEN size END) * 8. / 1024 AS DECIMAL(8,2))
, row_size_mb = CAST(SUM(CASE WHEN type_desc = "ROWS" THEN size END) * 8. / 1024 AS DECIMAL(8,2))
, total_size_mb = CAST(SUM(size) * 8. / 1024 AS DECIMAL(8,2))
, Kostenstelle = CAST((select value from sys.extended_properties WHERE     name =     "Kostenstelle") AS VARCHAR(10))
FROM sys.master_files WITH(NOWAIT)
WHERE database_id = DB_ID()
GROUP BY database_id
'

DECLARE @DatabasesKst TABLE
(
  database_name VARCHAR(50),
  log_size_mb DECIMAL(8,2),
  row_size_mb DECIMAL(8,2),
  total_size DECIMAL(8,2),
  Kostenstelle VARCHAR(100)
)

INSERT  INTO @DatabasesKst
EXEC sp_MSforeachdb @command

select * from @DatabasesKst

Answer 2

INSERT如果您在查询中添加语句，您可以在某些数据库中创建表并将结果保存在该表中：

DECLARE @command varchar(4000)
SELECT @command = '
USE [?] 
INSERT INTO <DbName>.<SchemaName>.<TableName>
SELECT 
database_name = DB_NAME(database_id)
...