Cli*_*rum 2 backbone.js parse-platform parse-cloud-code
我有两个问题:
logbookEntries,然后将其计为我帐户上的两个Parse 请求,因为它是两个 Parse 查询?这是代码:
Parse.Cloud.define("logbookEntries", function(request, response) {
//::: Query 1 :::
var firstQuery = new Parse.Query("Logbook");
var returnData = [];
firstQuery.find().then(function(firstResults) {
returnData[0] = firstResults;
}).then(function(result) {
//::: Query 2 :::
var secondQuery = new Parse.Query("Logbook");
secondQuery.find().then(function(secondResults))
returnData[1] = secondResults;
}).then(function(result) {
response.success(returnData);
}, function(error) {
response.error(error);
});
});
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提前致谢。
你的代码实际上应该是:
Parse.Cloud.define("logbookEntries", function(request, response) {
//::: Query 1 :::
var firstQuery = new Parse.Query("Logbook");
var returnData = [];
firstQuery.find().then(function(firstResults) {
returnData[0] = firstResults;
var secondQuery = new Parse.Query("Logbook");
return secondQuery.find();
}).then(function(result) {
returnData[1] = result;
response.success(returnData);
}, function(error) {
response.error(error);
});
});
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或者,更好的结构方式是:
Parse.Cloud.define("logbookEntries", function(request, response) {
var firstQuery = new Parse.Query("Logbook");
var secondQuery = new Parse.Query("Logbook");
var promises = [];
promises.push(firstQuery.find());
promises.push(secondQuery.find());
Parse.Promise.when(promises).then(function(result1, result2) {
var returnData = [];
returnData[1] = result1;
returnData[2] = result2;
response.success(returnData);
}, function(error) {
response.error(error);
});
}
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