Stackoverflow在数组中找到min和max时出错？

Question

我正在研究一个问题,以找到数组中的最小值和最大值.我有我的下面的程序,每当我运行它,我看到java.lang.StackOverflowError:

public class MinMaxInArray {

    public static void main(String[] args) {
        int a1[] = { 3, 4, 2, 6, 8, 1, 9, 12, 15, 11 };
        Pair result = getMinMax(a1, 0, a1.length - 1);

        System.out.println("Min: " + result.min);
        System.out.println("Max: " + result.max);
    }

    public static Pair getMinMax(int[] arr, int low, int high) {
        Pair result = new Pair();
        Pair left = new Pair();
        Pair right = new Pair();

        // if there is only one element arr= {1}
        if (low == high) {
            result.min = arr[low];
            result.max = arr[high];
        }

        // if there are two element arr={1,2}
        if (high == low + 1) {
            if (arr[low] > arr[high]) {
                result.max = arr[low];
                result.min = arr[high];
            } else {
                result.max = arr[high];
                result.min = arr[low];
            }
            return result;
        }
        // if there are more than 2 elements
        int mid = (low + high) / 2;
        left = getMinMax(arr, low, mid);
        right = getMinMax(arr, mid + 1, high);

        if (left.min < right.min) {
            result.min = left.min;
        } else {
            result.min = right.min;
        }
        if (left.max > right.max) {
            result.max = left.max;
        } else {
            result.max = right.max;
        }
        return result;

    }

    static class Pair {
        int min;
        int max;
    }
}

为什么抛出这个错误是什么意思？我怎样才能解决这个问题？

Answer 1

你return result;在这段代码中忘记了:

// if there is only one element arr= {1}
    if (low == high) {
        result.min = arr[low];
        result.max = arr[high];
        return result;
    }